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jarptica [38.1K]
3 years ago
14

Even though earth has ____ mass than the sun, the moon orbits earth because it much nearer to it.

Physics
2 answers:
julsineya [31]3 years ago
7 0

Answer:

The word that fills the blank is:

  • Even though earth has <u>less</u> mass than the sun, the moon orbits earth because it much nearer to it.

Explanation:

Two very important factors intervene to be affected by the gravity of a body:

  1. body mass.
  2. The distance from the celestial body.

Although the sun has a distance many times greater than Earth (<u>1,989 × 10 ^ 30 kg and 5,972 × 10 ^ 24 kg respectively</u>), the moon orbits the Earth since <u>the distance between these two is 384,400 km</u>, a distance very small when compared to <u>the distance to the sun which is approximately 149.6 million km</u>.

kozerog [31]3 years ago
3 0

Even though the Earth has less mass than the Sun, the moon orbits Earth because it’s much nearer to it.

<u>Explanation :</u>

The fact is that the Moon orbits both the Sun and the Earth. On looking at the orbit of the Moon, it orbits in the same manner the way Earth does, but in a Spiro graph pattern along with orbiting the Earth with a small wobble to it.  

Since the Sun has greater distance from the Moon as compared to the Earth (around 400 times), the gravity of Earth draws better impact on the Moon.  

The escape velocity of the Moon is about 1.2 km/s at the distance from the Earth which is not sufficient to get ripped away from the Earth.  

Hence, the moon orbits the Earth along with orbiting the Sun together with the Earth, but seems as if it only orbits the Moon.

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A car is driving at 99 km/h, calculate the distance it travels in 70 minutes.
Lapatulllka [165]

Answer:

The distance the car travels is 115500 m in S.I units

Explanation:

Distance d = vt where v = speed of the car and t = time taken to travel

Now v = 99 km/h. We now convert it to S.I units. So

v = 99 km/h = 99 × 1000 m/(1 × 3600 s)

v = 99000 m/3600 s

v = 27.5 m/s

The speed of the car is 27.5 m/s in S.I units

We now convert the time t = 70 minutes to seconds by multiplying it by 60.

So, t = 70 min = 70 × 60 s = 4200 s

The time taken to travel is 4200 s in S.I units

Now the distance, d = vt

d = 27.5 m/s × 4200 s

d = 115500 m

So, the distance the car travels is 115500 m in S.I units

8 0
3 years ago
A deuterium atom is a hydrogen atom with a neutron added to its nucleus. Approximate the binding energy of this nucleus, given t
Mademuasel [1]

Answer:

c. 2 MeV.

Explanation:

The computation of the binding energy is shown below

= [Zm_p + (A - Z)m_n - N]c^2\\\\=[(1) (1.007825u) + (2 - 1 ) ( 1.008665 u) - 2.014102 u]c^2\\\\= (0.002388u)c^2\\\\= (.002388) (931.5 MeV)\\\\=2.22 MeV

= 2 MeV

As 1 MeV = (1 u) c^2

hence, the binding energy is 2 MeV

Therefore the correct option is c.

We simply applied the above formula so that the correct binding energy could come

And, the same is to be considered

8 0
3 years ago
In what ways can students use time management? Check all that apply.
Korvikt [17]

Answer: the answer is A, C, E

Explanation:

Time management is apart of your study schedule so you will need to determine when to study, same goes with how to use ur study time, lastly it helps create ur study schedule to help find out what time you are free to study. :)

7 0
3 years ago
1. The planet Jupiter completes a revolution of the sun in 11.5 years. Express it in seconds. Given that one year= 3.154 × 10^7
xenn [34]

Answer:

The planet Jupiter completes one revolution of the sun in 362710000 seconds. Long time, right?

Explanation:

3.154x10^7=3.154x10000000=31540000

11.5x31540000=362710000

7 0
2 years ago
An airplane is flying through a thundercloud at a height of 2 000 m. (this is a very dangerous thing to do because of updrafts,
tester [92]
It is given that an<span> airplane is flying through a thundercloud at a height of 2000 m.
</span><span>
Since the parity of charges is opposite and the airplane lies between the two charges and both the electric fields are in the same direction at the plane. Therefore, the magnitudes of the electric field at the aircrafts will add up.
Now, check the image to see the calculations:

</span>

4 0
3 years ago
Read 2 more answers
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