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jarptica [38.1K]
3 years ago
14

Even though earth has ____ mass than the sun, the moon orbits earth because it much nearer to it.

Physics
2 answers:
julsineya [31]3 years ago
7 0

Answer:

The word that fills the blank is:

  • Even though earth has <u>less</u> mass than the sun, the moon orbits earth because it much nearer to it.

Explanation:

Two very important factors intervene to be affected by the gravity of a body:

  1. body mass.
  2. The distance from the celestial body.

Although the sun has a distance many times greater than Earth (<u>1,989 × 10 ^ 30 kg and 5,972 × 10 ^ 24 kg respectively</u>), the moon orbits the Earth since <u>the distance between these two is 384,400 km</u>, a distance very small when compared to <u>the distance to the sun which is approximately 149.6 million km</u>.

kozerog [31]3 years ago
3 0

Even though the Earth has less mass than the Sun, the moon orbits Earth because it’s much nearer to it.

<u>Explanation :</u>

The fact is that the Moon orbits both the Sun and the Earth. On looking at the orbit of the Moon, it orbits in the same manner the way Earth does, but in a Spiro graph pattern along with orbiting the Earth with a small wobble to it.  

Since the Sun has greater distance from the Moon as compared to the Earth (around 400 times), the gravity of Earth draws better impact on the Moon.  

The escape velocity of the Moon is about 1.2 km/s at the distance from the Earth which is not sufficient to get ripped away from the Earth.  

Hence, the moon orbits the Earth along with orbiting the Sun together with the Earth, but seems as if it only orbits the Moon.

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The position of an electron is given by , with t in seconds and in meters. At t = 3.99 s, what are (a) the x-component, (b) the
egoroff_w [7]

Answer:

A. Vx = 3.63 m/s

B. Vy = -45.73 m/s

C. |V| = 45.87 m/s

D. θ = -85.46°

Explanation:

Given that position, r, is given as:

r = 3.63tˆi − 5.73t^2ˆj + 8.16ˆk

Velocity is the derivative of position, r:

V = dr/dt = 3.63 - 11.46t^j

A. x component of velocity, Vx = 3.63 m/s

B. y component of velocity, Vy = -11.46t

t = 3.99 secs,

Vy = - 11.46 * 3.99 = -45.73 m/s

C. Magnitude of velocity, |V| = √[(-45.73)² + 3.63²]

|V| = √(2091.2329 + 13.1769)

|V| = √(2104.4098)

|V| = 45.87 m/s

D. Angle of the velocity relative to the x axis, θ is given as:

tanθ = Vy/Vx

tanθ = -45.73/3.63

tanθ = -12.6

θ = -85.46°

7 0
3 years ago
A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside
Alexeev081 [22]

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

4 0
3 years ago
Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?
Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

KE_1 = \dfrac{1}{2}mv^2

2000= \dfrac{1}{2}mv^2........(1)

now, speed of the car is doubled

v' = 2 v

KE_2 = \dfrac{1}{2}mv'^2

KE_2 = \dfrac{1}{2}m(2v)^2

from equation (1)

KE_2 = 4\times \dfrac{1}{2}m(v)^2

KE_2 = 4\times 2000

KE_2 = 8000\ J

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

8 0
2 years ago
How much power does a crane develop doing 60,000 J of work in<br> 5.00minutes?
larisa [96]

Answer: 200W

Explanation: P = W/T

60,000 / (5*60) = 200

4 0
2 years ago
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi
marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0
2 years ago
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