Answer:
the knee extensors must exert 15.87 N
Explanation:
Given the data in the question;
mass m = 4.5 kg
radius of gyration k = 23 cm = 0.23 m
angle ∅ = 30°
∝ = 1 rad/s²
distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m
using the expression;
ζ = I∝
ζ = mk²∝
we substitute
ζ = 4.5 × (0.23)² × 1
ζ = 0.23805 N-m
so
from; ζ = rFsin∅
F = ζ / rsin∅
we substitute
F = 0.23805 / (0.03 × sin( 30 ° )
F = 0.23805 / (0.03 × 0.5)
F F = 0.23805 / 0.015
F = 15.87 N
Therefore, the knee extensors must exert 15.87 N
Answer:
v =3.41 m/s
Explanation:
given,
mass of block 1 = 6 Kg
mass of another block 2 = 4 Kg
coefficient of friction = 0.3
Assuming 6 Kg block is attached to the spring of spring constant 350 N/m
and distance between the two block is equal to 0.5 m
using formula
U = 43.75 J
using conservation of energy
KE = U - f.d
where f is the frictional force acting
v =3.41 m/s
6. gas
7. liquid
8. gas
9. does not change
10. boiling point
Answer:
12m/s
Explanation:
Given parameters:
Power = 6.5 x 10⁴W
Force = 5.5 x 10³N
Unknown:
The resulting velocity = ?
Solution:
The velocity of a body is related to force and power using the expression below;
Power = Force x velocity
Insert the parameters and solve for velocity
6.5 x 10⁴ = 5.5 x 10³ x velocity
velocity = 
= 12m/s
The magnitude of their resultant vector is 4.6 meters/seconds
Since we are to add the velocity vectors in order to find the magnitude of their resultant vector.
Hence:
Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)
Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds
Resultant vector magnitude 4.6 meters/seconds
Inconclusion The magnitude of their resultant vector is 4.6 meters/seconds
Learn more here:
brainly.com/question/11134601
