Answer:
377 nm
Explanation:
Number of lines per meter is, 
Grating element is, 
![=1.8868 \times 10^{-6} \mathrm{~m}[tex] Order is, n=5 Condition for maximum intensity is, [tex]d \sin \theta=n \lambda](https://tex.z-dn.net/?f=%3D1.8868%20%5Ctimes%2010%5E%7B-6%7D%20%5Cmathrm%7B~m%7D%5Btex%5D%0A%3C%2Fp%3E%3Cp%3EOrder%20is%2C%20n%3D5%0A%3C%2Fp%3E%3Cp%3ECondition%20for%20maximum%20intensity%20is%2C%20%5Btex%5Dd%20%5Csin%20%5Ctheta%3Dn%20%5Clambda)
It would do exactly what a rock or a frisbee does when you toss it.
After the engines cut off, it couldn't get any more energy from
anywhere, and after that, as it pushed air aside to get through,
and had air molecules scraping against it, those would slowly
rob kinetic energy from it. Sooner or later it would run out of
kinetic energy, start falling, and it would eventually make either
a big 'SPLOOSH' or else a big 'CRUNCH', depending on exactly
where it returned to Earth's surface.
The answer in the first space provided is realistic whereas
the second space provided is fantastic. The correct answer would be letter B.
In realistic, it has many views in which the frame is the
window on the world whereas fantastic depicts imagination or remotes from
reality.
Answer:
1832
Explanation:
From;
Δp Δx = h/4π
Δp = uncertainty in momentum
Δx = uncertainty in position
h= Plank's constant
But p =mv hence, Δp= Δmv
m= mass, v= velocity
mass of electron = 9.11 * 10^-31 Kg
Mass of proton = 1.67 * 10^-27 Kg
since m is a constant,
Δv = h/Δxm4π
For proton;
Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10
Δv = 315 ms-1
For electron;
Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10
Δv = 577000 ms-1
Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832
