W=20 e(-kt)
A. Rearranging gives k= -(ln(w/20)/t
Substituting w= 10 and solving gives k=0.014
B. Using W=20e(-kt). After 0 hours, W=20. After 24 hours, W=14.29g. After 1 week (24x7=168h) W=1.9g
C. Rearranging gives t=-(ln(10/20)/k. Substituting w=1 and solving gives t=214 hours.
D. Differentiating gives dW/ dt = -20ke(-kt). Solving for t=100 gives dW/dt = 0.07g/h. Solving for t=1000 gives 0.0000002g/h
E. dW/dt = -20ke(-kt). But W=20e(-kt) so dW/dt = -kW
Sound Waves will be an example of mechanical waves.. hope this helps!
Answer:
The difference between P-N junction diode and extrinsic semiconductor is the allowable direction of flow of current
The extrinsic semiconductor can allow current to flow in both directions while the P-N junction diode permits only a unidirectional flow of current
Explanation:
A semiconductor is a substance that has an intermediate conductivity between that of conductors and non conductors
Examples of semiconductors include germanium and cadmium selenide
A semiconductor to which impurities has been added (an activity known as doping) is an extrinsic semiconductor
Based on the functioning of a semiconductor, doping result in the formation of one of two types of semiconductors including;
1) N-type semiconductor that has an extra electron and the charge carriers are electrons
2) P-type semiconductor that has one less (-e⁻) electron and holes are the charge carriers
An extrinsic semiconductor can conduct allow the flow of electricity in both ways
A P-N junction diode consists of both the P and N-type extrinsic semiconductors arranged such that current can flow in only one direction.
Therefore, the difference is that the extrinsic semiconductor can allow current flow in both directions while the P-N junction diode permits only a unidirectional flow of current.
