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yKpoI14uk [10]
3 years ago
6

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s ?

Physics
1 answer:
Grace [21]3 years ago
4 0

Answer:

The momentum, p = 6 kg • m/s

Explanation:

Given that,

Mass of the object, m = 5 Kg

Velocity of the object, v  = 1.2 m/s

The momentum of the body is defined as the product of the mass and velocity of the body. It is denoted by the letter 'p'

                                      p = mv

Substituting the values in the above equation

                                      p = 5 Kg x 1.2 m/s

                                         = 6 kg • m/s

Hence, the momentum of the object is p = 6 kg • m/s

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Which type of stress is most likely the cause of irritability?
masha68 [24]

Answer:

The correct answer is - distress.

Explanation:

Eustress is a type of stress that is beneficial to person and caused by adrenaline. Hypostress is a stress that is caused due to boredom or no work. It is stress comes with wasting the time.

Distress is the bad stress caused by anxiety, sadness, grief, and such type of stress that is caused irritability. Irritability is caused not just by stress but many factors.

4 0
3 years ago
A car moving along a straight level road has an initial speed of 3 m s-1 and its acceleration is 2 m s-2? What
BlackZzzverrR [31]

Answer:

13 ms-1

Explanation:

7 0
4 years ago
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A ball rolls at 3 meters per second. how much time does it take for the ball to roll 6 meters
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3 years ago
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A point on the string of a violin moves up and down in simple harmonic motion with an amplitude of 1.24 mm and frequency of 875
mario62 [17]

Using

V = Amplitude x angular frequency(omega)

But omega= 2πf

= 2πx875

=5498.5rad/s

So v= 1.25mm x 5498.5

= 6.82m/s

B. .Acceleration is omega² x radius= 104ms²

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3 years ago
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The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou
zlopas [31]

Answer:

q = 3.6 10⁵  C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

          r = 6 , 37 106 m

          E = k q / r²

          q = E r² / k

          q = \frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}

          q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

           r = 0.6 r_ Earth

           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

           E = k q / r²

            q = E r² / k

            q = \frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}

            q = 3.6 10⁵  C

4 0
3 years ago
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