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Liono4ka [1.6K]
3 years ago
6

An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and

Chemistry
1 answer:
harina [27]3 years ago
3 0

Answer:

C=0.596\frac{J}{g\°C}

Explanation:

Hello there!

In this case, according to the first law of thermodynamics it is possible to compute the gained heat by the water as shown below:

Q=\Delta U+W\\\\Q=9185J+346J=9531 J

Thus, it is possible to solve for the specific heat of the gas as shown below:

Q=mC\Delta T\\\\C=\frac{Q}{m\Delta T}=\frac{9531J}{80.0g*(225-25)\°C}\\\\C=0.596\frac{J}{g\°C}

Best regards!

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Name 3 different uses for nuclear technology
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Ammonia and oxygen react to form nitrogen monoxide and water. Construct your own balanced equation to determine the amount of NO
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Answer:

NO would form 65.7 g.

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Explanation:

Given data:

Moles of NH₃ = 2.19

Moles of O₂ = 4.93

Mass of NO produced = ?

Mass of  produced H₂O = ?

Solution:

First of all we will write the balance chemical equation,

4NH₃ + 5O₂   →   4NO + 6H₂O

Now we will compare the moles of NO and H₂O with ammonia from balanced chemical equation:

NH₃  :   NO                                   NH₃  :   H₂O

4     :    4                                          4    :      6

2.19   :    2.19                                 2.19  : 6/4 × 2.19 = 3.285 mol

Now we will compare the moles of NO and H₂O with oxygen from balanced chemical equation:

O₂  :   NO                                               O₂ :   H₂O

5     :    4                                                  5     :    6

4.93   :   4/5×4.93 = 3.944 mol               4.93  : 6/5 × 4.93 = 5.916 mol

we can see that moles of water and nitrogen monoxide produced from the ammonia are less, so ammonia will be limiting reactant and will limit the product yield.

Mass of water = number of  moles × molar mass

Mass of water = 3.285 mol × 18 g/mol

Mass of water = 59.13 g

Mass of nitrogen monoxide  = number of  moles × molar mass

Mass of nitrogen monoxide = 2.19 mol × 30 g/mol

Mass of nitrogen monoxide = 65.7 g

4 0
3 years ago
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The standard ambient temperature and pressure are

Temperature =298 K

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