Answer:
The horizontal velocity is constant at 16 m/s.
After 1 sec since v = a t then 9.8 m/s^2 * 1 sec = 9.8 m/s for the vertical velocity
V = (Vx^2 + Vy^2)^1/2 = (16^2 + 9.8^2)^1/2 = 18.8 m/s
Answer:
E 6.0sin132 = 4.46 km East
N 6.0cos132 = - 4.01 km = 4.01 km South
Explanation:
Answer:
Part a)
Weight on surface of other planet = 213.4 N
Part b)
Mass of the Astronaut = 66.0 kg
Part c)
Weight of the Astronaut on Earth = 646.8 N
Explanation:
Part A)
Weight of the Astronaut on the surface of the planet is given as
here we will have
also we have
now we have
Part B)
Mass of the Astronaut will always remains the same
So it will be same at all positions and all planets
So its mass will be
m = 66.0 kg
Part C)
Weight of the Astronaut on Earth is given as