Four (4.0) liters of helium gas are stored at 125 atm pressure. If the temperature and number of particles do not change, what w
ill be the new volume when the pressure is decreased to 50 atm? Show your work.
Please answer ASAP!!
1 answer:
Answer:
10 L
Explanation:
The only variables are pressure and volume, so we can use Boyle's Law:
p1V1 = p2V2
Data:
p1 = 125 atm; V1 = 4.0 L
p2 = 50 atm; V2 = ?
Calculation:
125 × 4.0 = 50V2
500 = 50 V2
V2 = 500/50 = 10 L
The new volume will be 10 L.
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