Answer:
Explanation:
Givens
vi = 0
a = 9.81
d = 4.50 m
vf = ?
Formula
vf^2 = vi^2 + 2 * a * d
Solution
Substitute the knowns into the formula
vf^2 =0 + 2 * 9.81 * 4.50
vf^2 = 88.29 Take the square root of both sides.
sqrt(vf^2) = sqrt(88.29)
vf = 9.40 m/s
The force of gravity = GMm / r^2, where G is gravitational constant, M is mass of one object, m is mass of another object, r is distance between them.
To make gravity smaller, decrease mass or increase distance.
To make gravity bigger, increase mass or decrease distance.
Answer:
3469.788 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
First rocket
Second rocket
When this will collide the total distance they would have covered would be 6000 m.
Hence at 13.72 seconds they will collide assuming they are launched at the same time.
The second rocket would have gone 3469.788 m when they collide
Answer:
57.885.8 kg weight of the container
Explanation:
The volume of the balloon * density of water = buoyant force of balloon
volume of a sphere = 4/3 pi r^3
= 4/3 pi * (1.5)^3 = 14.14 m^3 <===balloon volume
Now, find the buoyant force on the container ALONE ....
5.8 * 2.6 * 2.8 * 1027 = 43 364 kg <===== buoyant force
Now add the buoyant force of the balloon to find the weight
43 364 + 14.14 * 1027 = 57885.8 kg
