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alexandr1967 [171]

3 years ago

15

How much does a 200 kg car weigh?

1 answer:

adoni [48]3 years ago

5 0

These weights are minus the transmission which can push the car engine weight to around 600 pounds. While most formula ones cars are extremely fast the engines used are lightweight and weigh 100 kg or 210 pounds.

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Describe how the boiling point of water on top of a mountain would be different from its boiling point at sea level.

Sonbull [250]

Answer:

At elevated altitudes, any cooking that involves boiling or steaming generally requires compensation for lower temperatures because the boiling point of water is lower at higher altitudes due to the decreased atmospheric pressure.

Explanation:

7 0

3 years ago

The unit of power of a lens is.<br>(a) Metre<br>(b) Dyne<br>(c) Dioptre

zhenek [66]

Answer:

c. dioptre that's the answer.

5 0

3 years ago

Read 2 more answers

How much work would be needed to raise the payload from the surface of the moon (i.e., x = r) to an altitude of 5r miles above t

Cloud [144]

Let the data is as following

mass of payload = "m"

mass of Moon = "M"

now we know that we place the payload from the position on the surface of moon to the position of 5r from the surface

So in this case we can say that change in the gravitational potential energy is equal to the work done to move the mass from one position to other

so it is given by

$W = U_f - U_i$

we know that

$U_f = -\frac{GMm}{6r}$

$U_i = -\frac{GMm}{r}$

now from above formula

$W = -\frac{GMm}{6r} + \frac{GMm}{r}$

$W = \frac{5GMm}{6r}$

so above is the work done to move the mass from surface to given altitude

7 0

3 years ago

A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the hor

Nesterboy [21]

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

$a = 19 * 0.3048 = 5.8 m$

now we can use the formula of horizontal range

$R = \frac{v_o^2 sin2\theta}{g}$

$5.8 =\frac{ v_o^2 sin(2*40)}{9.8}$

$5.8 = \frac{v_o^2 * sin80}{9.8}$

$v_o^2 = 57.7$

$v_o = 7.6 m/s$

<u>so its initial speed must be 7.6 m/s</u>

8 0

4 years ago

3N<br> 3 N<br> What is the net force of the box?

zepelin [54]

6N I think I’m pretty sure

3 0

3 years ago