Answer:

Explanation:
Given data
Mass m=67.0 kg
Final Speed vf=8.00 m/s
Initial Speed vi=2.00 m/s
Distance d=25.0 m
Force F=30.0 N
From work-energy theorem we know that the work done equals the change in kinetic energy
W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²
And

So

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N
So
Answer:
Buffalo, NY
Explanation:
Temperature in Buffalo, NY = -29°C
In order to compare the temperatures we need to convert them to the same scale.

So, the temperature in Buffalo, NY was -20.2°F and the temperature in Anchorage, AL was 19°F.
Hence, it was colder in Buffalo, NY than in Anchorage, AL.
An initiator is someone who starts something. Example: She initiated the fight.
Answer:
M = 222 fringes
Explanation:
given
λ = 559 n m = 559 × 10⁻⁹ m
radius = 0.026 mm = 0.026 ×10⁻³ m
length of the glass plate = 22.1 ×10⁻² m
using relation


= 221.79
= 221 (approx.)
hence no of bright fringe
M = m + 1
= 221 +1
M = 222 fringes