Question

A flight attendant pulls her 70.0 N flight bag a distance of 253 m along a level airport floor at a constant velocity. The force she exerts is 40.0 N at an angle of 52 degrees above the horizontal. Find the following: a) the work she does on the flight bag b) the work done on the flight bag c) the coefficient of kinetic friction between the flight bag and the floor.

Answer 1

Answer:

6230.49413 J

0 J

0.63998

Explanation:

F = Force = 40 N

$\theta$ = Angle = 52°

Work done is given by

$W=Fscos50\\\Rightarrow W=40\times 253\times cos52\\\Rightarrow W=6230.49413\ J$

The work she does on the flight bag is 6230.49413 J

The work done on the flight bag will be the opposite of the work done by the flight attendant

$W=-6230.49413\ J$

So net work will be

$W_n=6230.49413-6230.49413\\\Rightarrow W_n=0$

The net work done on the flight bag is 0 J

Coefficient of friction is given by

$\mu=\dfrac{F_f}{F_N}\\\Rightarrow \mu=\dfrac{F_f}{F_g-F_{app}}\\\Rightarrow \mu=\dfrac{40cos52}{70-40sin52}\\\Rightarrow \mu=0.63998$

The coefficient of friction is 0.63998