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3 years ago

Why do pengiuns have beards

Chemistry

2 answers:

rodikova [14]3 years ago

8 0

Answer:

no they do not

Explanation:

yan [13]3 years ago

5 0

Answer:

It's just...Hair grown there...i guess it just grows as a male humans would

Explanation:

hope this helps.

You might be interested in

Define law of conservation of mass

horrorfan [7]

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction. Hope this helps!

7 0

3 years ago

Question 13 of 32

jarptica [38.1K]

Answer:

Explanation:

this should be obvious if you read it haha

3 0

3 years ago

A liquid mixture of 0.400 mole fraction ethanol and 0.600 methanol was placed in an evacuated (i.e., no air) bottle and after ma

deff fn [24]

Answer:

mole fraction methanol = 0.76

mole fraction ethanol = 0.24

Explanation:

Raoult´s law gives us the partial vapor pressure of a component in solution as the product of the mole fraction of the component and the value of its pure pressure:

PA = X(A) x Pº(A)

where PA is the partial vapor pressure of component A, X(A) is the mole fraction of A, and Pº(A) its pure vapor pressure.

From reference literature the pure pressures of methanol, and ethanol are at 25 ºC :

PºCH₃OH = 16.96 kPa

PºC₂H₅OH = 7.87 kPa

Given that we already have the mole fractions, we can calculate the partial vapor pressures as follows:

PCH₃OH = 0.600 x 16.96 kPa = 10.18 kPa

PC₂H₅OH = 0.400 x 7.87 kPa = 3.15 kPa

Now the total pressure in the gas phase is:

Ptotal = PCH₃OH + PC₂H₅OH = 10.18 kPa + 3.15 kPa = 13.33 kPa

and the mole fractions in the vapor will be given by:

X CH₃OH = PCH₃OH / Ptotal = 10.18 kPa/ 13.33 kPa = 0.76

X C₂H₅OH = 1 - 0.76 = 0.24

4 0

3 years ago

Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life

skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

$\tt 3\times 12.4=37.2~hours$

3 0

3 years ago

Solid magnesium reacts with aqueous Iron(III) chloride to produce aqueous magnesium chloride and solid iron.

luda_lava [24]

Answer:

9÷2Mg2+2FeCl3 =3Mg3Cl2 +2Fe

3 0

4 years ago