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AfilCa [17]
3 years ago
12

Solutions of sodium acetate and acetic acid are combined in equal volume to produce a buffer. Identify the combination that will

produce the buffer with the highest buffer capacity. Select one: a. 0.01 M CH3COOH , 0.1 M CH3COONa b. 0.1 M CH3COOH , 0.1 M CH3COONa c. 0.1 M CH3COOH , 0.01 M CH3COONa d. 0.01 M CH3COOH , 0.01 M CH3COONa
Chemistry
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

Option b=> 0.1 M CH3COOH , 0.1 M CH3COONa.

Explanation:

In chemistry, when an acid or a base(alkali) is added to a solution and the solution pH does not change then we say that the solution is a BUFFER SOLUTION (that is a solution, upon the addition of acid or base will show resistance in pH value).

In order to be able to answer this question efficiently we have to consider the mathematical representation or Equation below;

pH = pKa + log ( [ A^-] / [HA] )--------------------------------------------------------------------(1).

What the mathematical representation or Equation (1) above is telling is is that if [A^-] or [HA] is high then there will be the production of buffer with higher buffer capacity.

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Nitrogen dioxide gas is formed by reaction of nitrogen monoxide gas and oxygen gas
NeTakaya

Answer:

For the formation of nitrogen dioxide, the reactants used are nitrogen monoxide and oxygen gas. 2 moles of nitrogen monoxide gas react with 1 mole of oxygen gas to produce 2 moles of nitrogen dioxide gas.

Explanation:

3 0
3 years ago
A writer may use all of the following techniques to lead the reader to a flashback EXCEPT:
Semenov [28]
I think that a writer may use all of the following techniques to lead the reader to a flashback EXCEPT: a. a memory
8 0
3 years ago
The reaction of an arrhenius acid with an arrhenius base produces water and
aleksandr82 [10.1K]

Answer: salt

Explanation:

Arrhenius acids are substances which dissociate in water to give H^+ ions.

HCl\rightarrow H^++Cl^-

Arrhenius bases are substances which dissociate in water to give OH^- ions.

NaOH\rightarrow Na^++OH^-

Thus when they combine, they neutralize each other and produce salt and water.

HCl+NaOH\rightarrow NaCl+H_2O

6 0
3 years ago
An experiment requires 0.52 M NH3(aq). The stockroom manager estimates that 15 L of the base is needed. What volume of 15 M NH3(
Bingel [31]

Answer: 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base.

Explanation:

But on diluting the number of moles remain same and thus we can use molarity equation.

C_1V_1(stock)=C_2V_2 (to be prepared)

where,

C_1 =concentration of stock solution = 15 M

V_1 = volume of stock solution = ?

C_2 = concentration of solution to be prepared = 0.52 M

V_2 = volume of solution to be prepared = 15 L

15\times V_1=0.52\times 15

V_1=0.52L

Thus 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base

8 0
3 years ago
HELP ASAP!!!
Scorpion4ik [409]
<h3>Answer:  A) 3.5 mol/L</h3>

Explanation:

To determine the molarity, we have to find the number of moles in the volume given, and then extrapolate to find the number of moles that would be in 1 L.

<u>Determine the moles in the given volume</u>

moles of LiCl = mass ÷ molar mass

                       = 139.9 g ÷ 42.39 g/mol

                       = 3.30 mol

<u>Find the moles in 1 L</u>

    Since 930 mL of LiCl    =   3.30 mol

    then 1000 mL of LiCl    =   (3.30 mol × 1000 mL/L) ÷ 930 mL

                                           =  3.55 mol/L

4 0
2 years ago
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