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3 years ago

What is the hybridization of the central atom in the trichlorostannanide anion?

Chemistry

1 answer:

Mademuasel [1]3 years ago

8 0

Answer:

sp²

Explanation:

The trhichlorostannanide anion has molecular formula SnCl₃⁻, Sn is the central atom, which is at the group 14 of the periodic table, so it has 4 valence electrons. It must form 4 bonds to be stable.

In the anion, the tin (Sn) forms 3 bonds, so, it has 1 electron that is isolated. According to the VSEPR theory, the geometry of a molecule depends on the bonded electrons and the lone pairs, because the repulsive force between them will form the angles of the molecule.

Thus, only the bonded electrons will contribute, and because of that, the geometry will be trigonal planar.

To form the bonds, the subshells (s, p, d, f) of the atoms in the bond must interact. But, only isolated electrons can bond, so, to be stable and form the compounds, some atoms have hybrids shells, which are formed by the join of subshells.

The hybridization can be found by the determination of how many bonds are done, or by the geometry. For a trigonal planar geometry, the hybridization is sp², which means that the orbital is formed by one orbital s and two orbitals p.

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At a temperature of -33.0 degrees C, a sample of confined gas exerts a pressure of 53.3 kPa. If volume remains constant, at what

Rasek [7]

Answer: 598.9K = 325.9°C

Explanation:

P1= 53.3kPa T1= -33+273=240K

P2=133kPa , T2= ?

Applying P1/T1 = P2/T2

Substitute and Simplify

53.3/240 = 133/T2

T2= 598.9K = 325.9°C

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3 years ago

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Explanation:

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3 years ago

Which of the following best describes an empirical formula?

Monica [59]

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

C₂H₆O₂ Consist of Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

C : H : O

2 : 6 : 2

Divide the ratio by two to get simplest ratio

C : H : O

2/2 : 6/2 : 2/2

1 : 3 : 1

So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

Empirical formula of C₂H₆O₂ = CH₃O

So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

6 0

3 years ago

One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

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3 years ago

Water molecules are highly _______ and are always _________.

anyanavicka [17]

Water molecules are highly packed and are always near each other.

7 0

2 years ago