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Help me with this please thank you

1 answer:

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Birds have to go to south to migrate, birds are big and some are small, birds have good eye sit this is for the first one

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3 years ago

A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

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Answer:A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

A. 10.7 s

B. 2.18 s

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D. 0.0935 s

Explanation:

A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?

A. 10.7 s

B. 2.18 s

C. 0.374 s

D. 0.0935 s

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An object's weight is dependent upon its location in the universe. Why is this true? A. This is true because weight is the amoun

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(a) Calculate the number of free electrons per cubic meter for gold assuming that there are 1.5 free electrons per gold atom. Th

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Answer:

Part A:

$n=8.85*10^{28}m^{-3}$

Part B:

$Electron Mobility=3.03*10^{-3} m^2/V$

Explanation:

Part A:

To calculate the number of free electrons n we use the following formula::

n=1.5N-Au

Where N-Au is number of gold atoms per cubic meter

$N-Au=\frac{Density*Avogadro Number}{atomic weight}$

$Density = 19.32g/cm^3$

$Avogadro Number=6.02*10^{23} atoms/mol$

$Atomic weight=196.97g/mol$

So:

$n=1.5*\frac{Density*Avogadro Number}{atomic weight}$

$n=1.5*\frac{19.32*6.02*10^{23}}{196.97}$

$n=8.85*10^{28}m^{-3}$

Part B:

$Electron Mobility=\frac{Elec-conductivity}{n * charge on electron}$

n is calculated above which is 8.85*10^{28}m^{-3}

Charge on electron=1.602*10^{-19}

Elec- Conductivity= 4.3*10^{7}

$Electron Mobility=\frac{4.3*10^{7}}{ 8.85*10^{28} * 1.602*10^{-19}}$

$Electron Mobility=3.03*10^{-3} m^2/V$

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