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Physics

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Oliga [24]3 years ago

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Answer:

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The density of gold is 19.3 g/cm^3. what is the mass of 24 cm^3 of gold?

maw [93]

Mass = Density * Volume

Density = 19.3 g/cm³

Volume = 24 cm³

Mass = Density * Volume = 19.3 g/cm³ * 24 cm³ = 463.2 g

Mass = 463.2 g

3 0

3 years ago

A horizontal pipe of inner diameter 2.2 cm carries water with a density of 1000.0 kg/m3 flowing at a rate of 1.5 kg/s. If the pi

EleoNora [17]

The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.

<h3> What is speed?</h3>

Speed is defined as the rate of change of the distance or the height attained.

The given data in the problem is;

The initial diameter is, $\rm d_1 = 2.2 \ cm$

initial radius,

$r_1 = \frac{d_1}{2} \\\\ r_1 = \frac{2.2}{2} \\\\ r_1 = 1.1\ cm$

The initial crossection area;

$\rm A_1 = \pi r_1^2 \\\\ \rm A_1 = 3.14 \times (1.1\times 10^{-2})^2 \\\\ \rm A_1 =3.8 \times 10^{-4} \ m^2$

The final crossection area;

$\rm A_2 = \pi r_2^2 \\\\ \rm A_2 = 3.14 \times ( 2 \times 10^{-2})^2 \\\\ \rm A_2 = 12.56 \ m^2$

The initial flow rate is;

R = density ×velocity ×area

$\rm R = \rho A V \\\\ 1.5 = 1000 \times V_1 \times 3.8 \times 10^{-4} \\\\ V_1 = 3.947 \ m/sec$

The speed of the water in the wider part will be;

From the continuity equation;

$\rm A_1 V_1 = A_2V_2 \\\\\ 3.8 \times 10^{-4} \times 3.947 = 12.56 \times 10^{-4} \times V_2 \\\\ V_2= 1.194 \ m/sec$

Hence, the speed of the water in the wider part will be 1.194 m/sec.

To learn more about the speed, refer to the link;

brainly.com/question/7359669

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2 years ago

Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A

Alisiya [41]

Answer:

0 j

Explanation:

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3 years ago

Which type of galaxy is too small for gravity to form it into an easily describable shape?

oksano4ka [1.4K]

If you think about it, irregular galaxies dont really have a describable shape, as you can tell by the name. So B.

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3 years ago

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A baseball player throws a baseball at a speed of 40 meters per second at an angle of 30 degrees. What is the velocity of projec

Vesna [10]

Answer:

The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 . To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

Hope it helpss :)

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2 years ago

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