A 4.0 kg block is resting on a rough horizontal table. The coefficient of static friction us is 0.60. The static friction betwee
1 answer:
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3s
Explanation:
Given parameters:
Mass of car = 1000kg
Force applied = 8000N
speed = 24m/s
Unknown:
time taken for the car to stop = ?
Solution:
According to newton's second law of motion; "the force on a body is the product of its mass and acceleration".
Force = mass x acceleration
let us find the acceleration of the car;
a = =
= 8m/s²
since the car is accelerating at a rate of 8m/s², when the brakes are applied, it will start decelerating at the constant rate, - 8m/s²
Applying the appropriate equation of motion;
V = U + at
V is the final velocity
U is the initial velocity
a is the acceleration
t is the time taken
final velocity = 0
0 = U + at
-U = at
-24 = -8t
t = 3s
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Newton's laws brainly.com/question/11411375
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If,
then, with 3x time t, (suppose, new distance is h)
Therefore, new distance h will be 9 times bigger than distance d.
answer: c