Answer:
v = 54 m/s
Explanation:
Given,
The maximum height of the flight of golf ball, h = 150 m
The velocity at height h, u = 0
The velocity of the golf ball right before it hits the ground, v = ?
Using the III equations of motion
<em> v² = u² + 2gh</em>
Substituting the given values in the above equation,
v² = 0 + 2 x 9.8 x 150 m
= 2940
v = 54 m/s
Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s
A beta particle followed by another beta particle. Consider it beta positive decay in which a proton decays to form a neutron,positron and electron neutrino.
Answer: Its applied force and friction, The friction is the drag and the applied force is you pushing
Answer:
Since there is a gravitational pull, you wouldn't reach the other side. You'd probably be floating in the center of the earth.
