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3 years ago

13

What is the maximum volume of 0.25 M sodium hypochlorite solution (NaOCl, laundry bleach) that can be prepared by dilution of 1.

00 L of 0.80 M NaOCl?

2 answers:

ehidna [41]3 years ago

8 0

Answer:

0.313L

Explanation:

0.25Mx1.00L=0.80Mx V2

so, 0.25x1.00/0.80=0.313L

Iteru [2.4K]3 years ago

7 0

Answer: 3.2L

Explanation:

C1 = 0.80M

V1 = 1L

C2 = 0.25M

V2 =?

C1V1 = C2V2

0.8 x 1 = 0.25 x V2

V2 = (0.8 x 1) /0.25 = 3.2L

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3 years ago

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What is the voltage of the voltaic cell Zn|Zn2+||Cu2+|Cu at 298 K if [Zn2+] = 0.2 M and [Cu2+] = 4.0 M? Cu2+ + 2e- → Cu Eo = +0.

OLga [1]

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Explanation :

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$E^o_{cell}=(+0.34V)-(-0.76V)$

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Now we have to calculate the emf or voltage of the cell.

Using Nernest equation at 298 K :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}$

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$E_{cell}=1.1-\frac{0.0592}{2}\log \frac{0.2}{4.0}$

$E_{cell}=1.14V$

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