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Orlov [11]
2 years ago
10

A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th

e rear wheels drive over the scale, it reads 6500 N. The distance between the front and rear wheels is 3.20 m Determine the distance between the front wheels and the truck's center of gravity.
Physics
1 answer:
aev [14]2 years ago
6 0

Answer:

x_2=1.60m

Explanation:

From the Question We are told that

Initial Force F_1=5800N

Final Force F_2=6500N

Distance between the front and rear wheels \triangle x=3.20 m

Since

 \triangle x=3.20 m

Therefore

 x_1+x_2=3.20

 x_1=3.20-x_2

Generally the equation for The center of mass is at x_2 is mathematically

given by

 x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}

 x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}

 2*F_1*x_2 =3.20F_1

 x_2=1.60m

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A 52.0-kg person, running horizontally with a velocity of +3.63 m/s, jumps onto a 15.2-kg sled that is initially at rest. (a) Ig
trasher [3.6K]

Answer:

The coefficient of kinetic friction between the sled and the snow is 0.0134

Explanation:

Given that:

M = mass of person = 52 kg

m = mass of sled = 15.2 kg

U = initial velocity of person = 3.63 m/s

u = initial velocity of sled = 0 m/s

After collision, the person and the sled would move with the same velocity V.

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The velocity of the sled and person as they move away is 2.81 m/s

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Using the formula:

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The coefficient of kinetic friction between the sled and the snow is 0.0134

3 0
3 years ago
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