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2 years ago

How many moles of NO gas are formed from 2.25 moles of nitrogen?

Chemistry

1 answer:

VikaD [51]2 years ago

7 0

Hey there!

A mole is measured in atoms, molecules, particles. It's kind of a loose sort of measurement, just unit of the substance.

Since there is a ratio of 1 to 1 nitrogen to oxygen, there will be the same amount of molecules as atoms of nitrogen.

2.25 moles of NO gas are formed from 2.25 moles of nitrogen.

Hope this helps!

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krek1111 [17]

Explanation:

The form AZX denoted that;

Z = The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element.

A = Mass Number ( Sum of Neutrons and Protons)

X represents the element.

A. the copper isotope with 34 neutrons

X = Cu

Atomic Number of Copper, Z = 29

Mass Number, A = 29 + 34 = 63

63.29.Cu

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X = Cu

Atomic Number of Copper, Z = 29

Mass Number, A = 29 + 36 = 65

65.29.Cu

C. the potassium isotope with 21 neutrons

X = K

Atomic Number of Potassium, Z = 19

Mass Number, A = 19 + 21 = 40

40.19.K

D. the argon isotope with 22 neutrons

X = Ar

Atomic Number of Argon, Z = 18

Mass Number, A = 18 + 22 = 40

40.18.Ar

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2 years ago

7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken

Nana76 [90]

<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

$\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M$

Hence, the molarity of Iron (III) chloride is 0.622 M.

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2 years ago

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4.5 x 6.023 x 10^23 = 2.71035 x 10^24

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