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vampirchik [111]

3 years ago

5

An ostrich can run at speeds of up to 72 kilometers per hour. How long will it take an ostrich to run 1.5 kilometers at this top

speed?

1 answer:

tatiyna3 years ago

6 0

S=d/t
T=d/s
= 1.5/72
= 0.02 hours

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what type of simple machine is shown in the diagram?write the length and height of slope in it. Please help ASAP!!!

Akimi4 [234]

the machine shown in the diagram is called a tramp.

the height of the tramp is 5 and the length is 12

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Why do you lurch forward in a bus that suddenly slows? why do you lurch backward when it picks up speed? what law applies here?

AveGali [126]

The law applied here is Newton's first law, also known as, law of inertia.
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If you are moving and the bus suddenly stops, your body will lurch forward trying to retain its state of motion until it comes to rest and changes its state by the external force acted on it.

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3 years ago

How to tell how much work gravity does on something?

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By dropping a ball and seeing how long it takes to hit the ground or throw a ball up and time it as well

4 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 8.2 m apart, and are each playing a 78.0 Hz to

Stels [109]

Answer:6.298,4.1,1.9015

Explanation:

Wavelength= $\frac{velocity of sound }{frequency}$

= $\frac{343}{78}$ =4.397 m

Distance of 3rd speaker from speaker A is x

From B 78-x

Difference between the distances must be a whole number of wavelengths

First

$x-\left ( 8.2-x\right )=4.397$ for 1 st wavelength

2x=8.2+4.397=12.597

x=6.298m

second

For zero wavelength

$x-\left ( 8.2-x\right )=0$

2x=8.2

x=4.1m

Third

$\left ( 8.2-x\right )-x=4.397$

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6 0

3 years ago

The stiffness of a particular spring is 42 N/m. One end of the spring is attached to a wall. A force of 2 N is required to hold

Liula [17]

Answer:

$L_{o}=0.1224m$

Explanation:

Given data

Force F=2 N

Length L=17 cm = 0.17 m

Spring Constant k=42 N/m

To find

Relaxed length of the spring

Solution

From Hooke's Law we know that

$F_{spring}=k_{s}|s|\\F_{spring}=k_{s}(L-L_{o})\\ 2N=(42N/m)(0.17m-L_{o})\\2=7.14-42L_{o}\\-42L_{o}=2-7.14\\42L_{o}=5.14\\L_{o}=(5.14/42)\\L_{o}=0.1224m$

6 0

4 years ago