In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added
1 answer:
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Answer:
λ = 5.734 x 10⁻⁷ m = 573.4 nm
Explanation:
The formula of the Young's Double Slit experiment is given as follows:
where,
λ = wavelength = ?
L = distance between screen and slits = 8.61 m
d = slit spacing = 1.09 mm = 0.00109 m
Δx = distance between consecutive bright fringes = = 0.00453 m
Therefore,
<u>λ = 5.734 x 10⁻⁷ m = 573.4 nm</u>
Answer:
The speed of object B is 2 times of speed of object A.
Explanation:
Given that,
Kinetic energy of object A = 25 J
Mass of object B
Work done = -20 J
We need to calculate the factor of the speed of the object
Suppose the final kinetic energy is same for both object.
Put the value into the formula
Hence, The speed of object B is 2 times of speed of object A.
Answer:
5.33kg
Explanation:
Given parameters:
Velocity of eagle = 15m/s
Kinetic energy of the eagle = 600J
Unknown:
Mass of the eagle = ?
Solution:
The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical energy.
The formula of kinetic energy is given as;
Kinetic energy = m v²
where m is the mass, V is the velocity
substitute the parameters in the equation;
600 = x m x 15²
225m = 1200
m = = 5.33kg