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4 years ago

7

In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added

to the system. What was the total change in the internal energy of the system?

1 answer:

amid [387]4 years ago

7 0

Answer:

187 J

Explanation:

First Law of Thermodynamics :

ΔQ = ΔW + ΔU

ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

ΔW : Work. If it done by the system then positive and if it is done on system then negative.

ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

ΔQ = 79 J

ΔW = - 108 J

ΔU = ?

substituting the value in the equation:

79 = -108 + ΔU

∴ ΔU = 187 J

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