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2 years ago

Describe the progress of the formation of an ionic bond in terms of electrons

Chemistry

1 answer:

umka21 [38]2 years ago

3 0

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

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In a chemical equation what name does the left side have

Pachacha [2.7K]

A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>

4 0

3 years ago

What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?

const2013 [10]

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

5 0

3 years ago

Read 2 more answers

Type the letter of the correct answer in the blank space. The image shows the combustion of methane. Which equation represents t

Talja [164]

Answer:

CH4 + 2O2 → CO2 + 2H2O

Explanation:

7 0

2 years ago

What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?

kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $Al(OH)_3$ = 0.610 g

Molar mass of $Al(OH)_3$ = 78 g/mol

$\text{Number of moles}=\frac{0.610g}{78g/mol}$

Number of moles of $Al(OH)_3$ = 0.0078 moles

The reaction between $Al(OH)_3$ and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

$Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O$

By Stoichiometry,

1 mole of $Al(OH)_3$ reacts with 3 moles of HCl

So, 0.0078 moles of $Al(OH)_3$ will react with $\frac{3}{1}\times 0.0078$ = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

$0.0234moles=\frac{\text{Given mass}}{36.5g/mol}$

Mass of HCl required will be = 0.8541 grams

3 0

3 years ago

A unit of heat energy that was formerly used frequently was the calorie. Look up the definition of the calorie in your textbook

dybincka [34]

Answer and Explanation:

Calorie is the unit of heat energy . There are 2 units with the same name 'calorie' which is widely used.

'The amount of heat energy required to increase the temperature of 1 gram of water by mass by $1^{\circ}C$ or 1 K is known as small calorie or gram calorie'.

Another one is large calorie which can be defined as :

'The amount of heat energy required to make arise in temperature of water 1 kg by mass by $1^{\circ}C$ or 1 K is known as large calorie or kilcalorie and is represented as Cal or kcal'.

After the adoption of SI system, thee units of the metric system cal, C or kilocal are considered deprecated or obsolete with the SI unit for heat energy as 'joule or J'

1 cal = 4.184 J

1C or 1 kilocal = 4184 J

Calorimeter constant:

Calorimeter constant, represented as ' $C_{cal}$ ' is used to quantify the heat capacity or the amount of heat of a calorimeter.

It can be calculated by ther given formula:

$C_{cal}}={\frac {\Delta {H}}{\Delta {T}}}}$

where,

${\Delta {T}}$ = corresponding temperature change

${\Delta {H}$ = enthalpy change

Its unit is J/K or J/1^{\circ}C[/tex] which can be convertyed to cal/1^{\circ}C[/tex] by dividing the calorimeter constant by 4.184 or 4184 accordingly.

8 0

3 years ago