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r-ruslan [8.4K]
4 years ago
12

What is epsilon zero and why does it come into use, particularly in the case of Gauss's Law?

Physics
1 answer:
Paha777 [63]4 years ago
5 0
<span>Epsilon zero is permittivity of free space means how much air or vacuum permits electric field to travel from one charge to other.It is constant in the coulomb law. This allow Gauss's a lot easier to solve rather than using K</span>
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A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro
fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

Q=C\times V

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = C_1=2.81 \mu F=2.81\times 10^{-6} F

Charge of first capacitor = Q_1

Voltage across first capacitor = V_1=1220 V

Q_1=C_1V_1

Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C

Capacitance of first capacitor = C_2=6.61\mu F=6.61\times 10^{-6} F

Charge of second capacitor = Q_2

Voltage across first capacitor = V_2=560 V

Q_2=C_2V_2

Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C

Total capacitance in parallel combination:

C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F

Potential across both capacitors = V

V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V

756.88 Volts will be the potential difference across each capacitor.

8 0
3 years ago
Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three sec
ella [17]
<span><span>Your friend is bragging about his motorcycle. He claims that it can go from a stopped position to 50 miles per hour in three seconds. He is describing the motorcycle's

</span>Answer: </span>acceleration

Hope This Helps! :3
8 0
3 years ago
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A person who is good at caring for others might enjoy a career as a
julia-pushkina [17]
He or she would enjoying doing a job as a caretaker
5 0
3 years ago
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. At the same inst
kifflom [539]

Answer:

66.85 m

Explanation:

We are given that

Acceleration ,a=2.7m/s^2

Speed of truck, v=9.5 m/s

We have to find the distance beyond which the traffic signal will the automobile overtake the truck.

Initial speed of automobile, u=0

We know that

s=ut+\frac{1}{2}at^2

Using the formula

s=0+\frac{1}{2}(27)t^2=\frac{27}{2}t^2

For constant speed

Acceleration, a=0

Again

s=vt+0=9.5t

9.5t=\frac{27}{2}t^2

t=\frac{9.5\times 2}{2.7}=7.037s

Substitute the value of t

x=9.5(7.037)=66.85m

Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m

3 0
3 years ago
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
dimulka [17.4K]

Answer:

The power output of this engine is  P =  17.5 W

The  the maximum (Carnot) efficiency is  \eta_c  = 0.7424

The  actual efficiency of this engine is  \eta _a  = 0.46

Explanation:

From the question we are told that

    The temperature of the hot reservoir is  T_h = 1250 \ K

      The temperature of the cold reservoir  is  T_c  =  322 \ K

     The energy absorbed from the hot reservoir is E_h  = 1.37 *10^{5} \ J

       The energy exhausts into  cold reservoir is  E_c  = 7.4 *10^{4} J

The power output is mathematically represented as

      P  =  \frac{W}{t}

Where t is the time taken which we will assume to be 1 hour =  3600 s  

W is the workdone which is mathematically represented as

      W =  E_h  -E_c

substituting values

       W = 63000 J

So

    P =  \frac{63000}{3600}

    P =  17.5 W

The Carnot efficiency is mathematically represented as

          \eta_c  =  1 - \frac{T_c}{T_h}

         \eta_c  =  1 - \frac{322}{1250}

         \eta_c  = 0.7424

The actual efficiency is mathematically represented as

        \eta _a  =   \frac{W}{E_h}

substituting values

         \eta _a  =  \frac{63000}{1.37*10^{5}}

         \eta _a  = 0.46

     

7 0
4 years ago
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