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sveticcg [70]
3 years ago
7

A carver begins work on the following block of granite that weighs 2700 g. The dimensions of the block are 20 cm, 5 cm and 10 cm

. What is the density of the granite in g/cm³?
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

\text { "Density" of the given granite block is } 2.7 \mathrm{g} / \mathrm{cm}^{3} \text { . }

Explanation:

Density of an object is defined as the mass occupied per unit volume. “Density” is represented by “ρ”. Mathematically, \rho=\frac{m}{v} where, “m" mass of an object and "v" is volume of an object.

Given that,

Dimensions of the block are 20 cm, 5 cm and 10 cm.

\text { Volume of the block is } l \times b \times h

\text { Volume of the block is } 20 \times 5 \times 10

\text { Volume of the block is } 1000 \mathrm{cm}^{3} \text { . }

Mass of the block is 2700 g.

Substitute the given values in \rho=\frac{m}{v} to find density of a block.

\rho=\frac{2700}{1000}

\rho=2.7 \mathrm{g} / \mathrm{cm}^{3}

\text { "Density" of the given granite block is } 2.7 \mathrm{g} / \mathrm{cm}^{3}

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v_f= \frac{p_f}{m+M}= \frac{4.8 kg m/s}{0.1 kg+10 kg}=  0.48 m/s

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v_i =  \frac{p_f}{m}= \frac{4.8 kg m/s}{0.1 kg}=48 m/s
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