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sveticcg [70]
3 years ago
7

A carver begins work on the following block of granite that weighs 2700 g. The dimensions of the block are 20 cm, 5 cm and 10 cm

. What is the density of the granite in g/cm³?
Physics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

\text { "Density" of the given granite block is } 2.7 \mathrm{g} / \mathrm{cm}^{3} \text { . }

Explanation:

Density of an object is defined as the mass occupied per unit volume. “Density” is represented by “ρ”. Mathematically, \rho=\frac{m}{v} where, “m" mass of an object and "v" is volume of an object.

Given that,

Dimensions of the block are 20 cm, 5 cm and 10 cm.

\text { Volume of the block is } l \times b \times h

\text { Volume of the block is } 20 \times 5 \times 10

\text { Volume of the block is } 1000 \mathrm{cm}^{3} \text { . }

Mass of the block is 2700 g.

Substitute the given values in \rho=\frac{m}{v} to find density of a block.

\rho=\frac{2700}{1000}

\rho=2.7 \mathrm{g} / \mathrm{cm}^{3}

\text { "Density" of the given granite block is } 2.7 \mathrm{g} / \mathrm{cm}^{3}

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Despite a vigorous training schedule and careful meal planning, Anthony “hit the wall” at mile 12 of his half-marathon and he ha
Lorico [155]

Answer:

Condition of fatigue caused by depletion of glycogen

Explanation:

Let us examine how a body produces energy. There are two ways:

Fat metabolism

Fatty acids in the body help to capture adenosine triphosphate (ATP) which produces energy. On a per gram basis fatty acids yields the most ATP when oxidized completely.

Glycogen breakdown

the enzyme glycogen phosphorylase cleaves glycogen from the non reducing ends to produce monomers of glucose-1-phosphate. These monomers are used by the human body to supply energy.

When a person is exercising his/her VO₂ i.e., the oxygen consumption reaches maximum, here most of the energy comes from glycogen. While exercising most of the energy comes from glycogen breakdown.

So, when Anthony hit the wall it means that he has depleted his source of glycogen and can no longer produce glucose which provides him energy.

5 0
3 years ago
The lubrication of bone joints is a subject of ongoing medical research. Two bones connected at a joint do not touch. The bones
maks197457 [2]

The question is incomplete. The complete question is :

To measure the effective coefficient of friction in a bone joint, a healthy joint (and its immediate surroundings) can be removed from a fresh cadaver. The joint is inverted, and a weight is used to apply a downward force F⃗ d on the head of the femur into the hip socket. Then, a horizontal force F⃗ h is applied and increased in magnitude until the femur head rotates clockwise in the socket. The joint is mounted in such a way that F⃗ h will cause clockwise rotation, not straight-line motion to the right. The friction force will point in a direction to oppose this rotation.

Draw vectors indicating the normal force n⃗  (magnitude and direction) and the frictional force f⃗ f (direction only) acting on the femur head at point A.

Assume that the weight of the femur is negligible compared to the applied downward force.

Draw the vectors starting at the black dot. The location, orientation and relative length of the vectors will be graded

Solution :

The normal force represented by N is equal to the downward force, $F_d$ which is equal in magnitude but it is opposite in direction.

Also the frictional force acts always to oppose the motion because the bone starts moving in a clockwise direction. The frictional force that will be applied to the right direction so that the movement or the rotation at A is opposed.  

5 0
3 years ago
A 51.0-kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each
chubhunter [2.5K]

Answer:

Pressure = 9.94 x 10⁶ Pascals

Explanation:

given data

mass = 51 kg

radius = 0.400 cm

solution

we know Pressure that is express as here

Pressure = total force on an area ÷ the area of the area   .................1

and

Force is the woman's weight so weight will be

Weight = mass × gravity  .................2

put here value

Weight = 51 × 9.8 m/s²

Weight = 499.8 Newtons

and

Area of a circle of bottom of the heel = (π) × (radius)²    ...................3

put here value

Area = (π) × (0.40 cm)²

Area = 0.502654 cm²

Area = 0.0000502654 m²

and

now we put value in equation 1 we get

Pressure = force ÷ area

Pressure = 499.8 ÷ 0.0000502654

Pressure = 9943221.381 N/m²

Pressure = 9.94 x 10⁶ Pascals

6 0
3 years ago
One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
Eva8 [605]

Answer:

6666.67 Newtons

Explanation:

The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.

In this case:

  • mass= 0.1mg= 1*10^-7 kg
  • velocity= 4.00*10^3 m/s
  • time= 6.00*10^-8 s

Using velocity and time, acceleration can be calculated as:

  • a= 6.667*10^10 m/s²

Substituting these values into the formula F=ma, the answer is:

  • F= (1*10^-7)kg * (6.667*10^10) m/s²
  • F= 6666.67 Newtons of force
5 0
3 years ago
The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg/ m3.
sladkih [1.3K]

Answer:

P = 7196 [kPa]

Explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]

5 0
3 years ago
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