Question

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60 kg and has a horizontal velocity of 5 m/s just before the grab.Another acrobat has a mass of 50 kg and has a horizontal velocity of -3 m/s just before the grab.Their horizontal velocity immediately after they grab onto each other is:

Answer 1

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat,$m_1=60 kg$

Mass of another acrobat,$m_2=50 kg$

$v_2=-3 m/s$

$v_1=5 m/s$

We have to find their  velocity immediately after they grab  onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

$m_1v_1+m_2v_2=(m_1+m_2)V$

Substitute the values

$60\times 5+50(-3)=(60+50)V$

$300-150=110V$

$V=\frac{300-150}{110}=1.36m/s$