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Oliga [24]
3 years ago
7

A bowling ball is dropped on a moon from the height of 14 m. The acceleration of gravity on the moon is 4 m/s2. Determine the ti

me it took for the ball to crash at the surface. Round your answer to the nearest whole number.
b. 1 s
c. 4 s
d. 3 s​
Physics
1 answer:
goblinko [34]3 years ago
7 0

Answer:

4sec

Explanation:

Since we know the initial velocity=0, acceleration = -4; and the displacemnt =14, we use the equation d = vi • t + ½ • a • t2. So, just plug in the values and solve for t in this case it's 4 sec

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Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places
Olenka [21]

Answer:

The magnitude of V_{2} is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage V_{out} = 17.33

Resistance R_{1} = 3 kΩ

Voltage gain A_{v} = 4.33

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

     A_{v} = 1+\frac{R_{f} }{R_{1} }

   4.33 = 1+ \frac{R_{f} }{3 k }

     R_{f} ≅ 10 kΩ

For finding input voltage we use,

   A_{v} = \frac{V_{out} }{V_{2} }

    V_{2} = \frac{17.33}{4.33}

    V_{2} = 4 V

The Phase of V_{2} is zero because output voltage phase is 360°

Therefore, the magnitude of V_{2} is 4 V and phase of input voltage is zero

7 0
3 years ago
What are the disadvantages of using alcohol instead of mercury in a thermometer ?​
vichka [17]

Answer:

alcohol thermometers are used rather than Mercury thermometers in very cold regions because alcohol has a lower freezing point than Mercury.

Explanation:

6 0
3 years ago
2. What is the wavelength of the wave shown above?<br> a. 6m<br> b. 11<br> C 2m<br> d. 3m
Dafna1 [17]

Answer:

網站有中、英文版本,也有繁、簡體版,可通過每頁左上角的連結隨時網站有中、英文版本,也有繁、簡體版,可通過每頁左上角的連結隨時

Explanation:

7 0
3 years ago
Uma barra de ferro homogênea possui, a 20 °C, o comprimento de 6 m. Se o coeficiente de dilatação linear do ferro é 1,2 ∙ 10⁻⁵ °
Natali [406]

Answer:

25°C

Explanation:

Using the linear expansivity formula expressed as;

∝ = ΔL/lΔθ

∝ is coefficient of lineat expansion = 1.2 ∙ 10⁻⁵ °C⁻¹

ΔL is the change in length = 6.00036-6

ΔL = 0.00036m

l is the original length = 6m

Δθ is the change in temperature =θ₂-20

Substituting into the formula;

1.2 ∙ 10⁻⁵ °C⁻¹  = 0.00036/6(θ₂-20)

cross multiply

1.2 ∙ 10⁻⁵ * 6  = 0.00036/(θ₂-20)

7.2 ∙ 10⁻⁵= 0.00036/(θ₂-20)

0.00036 = 7.2 ∙ 10⁻⁵(θ₂-20)

0.00036 = 7.2 ∙ 10⁻⁵θ₂-144∙ 10⁻⁵

7.2 ∙ 10⁻⁵θ₂ = 0.00036+0.00144

7.2 ∙ 10⁻⁵θ₂ = 0.0018

θ₂ = 0.0018/0.000072

θ₂ = 25°C

Hence the temperature at which this bar must be acidic for its compression is 6,00036 m is 25°C

4 0
3 years ago
Push the plunger in the two syringes. Is your prediction correct? Why?​
4vir4ik [10]

Answer:

This is worded strangely.

4 0
3 years ago
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