Answer:
12 kg
Explanation:
q = 52,800 J
c = 880 J/(kg * K) Pretty sure you missed the kg here
ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)
q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg
The unit for measuring current is an " ammeter ".
The unit for measuring voltage is a " voltmeter ".
The unit of measure for electrical current is the " Ampere ".
The unit of measure for potential difference (voltage) is the " volt ".
D, small force for short time, as it has the least influence on the velocity.
C, momentum is velocity x mass, so if velocities are the same, then the object with less mass with have a lower momentum.
Answer:
9.0 m/s
Explanation:
The problem can be solved by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
is the acceleration of gravity
t is the time
When the ball reaches the maximum height, the velocity becomes zero. If we consider this as initial point of the motion, we can write
u = 0
The time it takes for the ball to go down from the maximum heigth to the ground is half the total time, so
And solving the formula for v, we find the final velocity:
So, the final speed is 9.0 m/s.
Q9. R₁ only.
Since the upper branch is cut at x, the circuit in this branch is not closed. No current will flow through this branch. In this case, the circuit becomes a series circuit and current only flows through R₁.
Q10. 3 pathways.
3 different resistors are connected in parallel, which means there will be three branches of parallel circuit, each with one resistor. Current can flow through 3 different branches, until the parallel circuits combine together again.
