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4 years ago

A ball is thrown upward. After reaching a

Physics

1 answer:

Triss [41]4 years ago

3 0

Answer:

9.0 m/s

Explanation:

The problem can be solved by using the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

$a=g=-9.8 m/s^2$ is the acceleration of gravity

t is the time

When the ball reaches the maximum height, the velocity becomes zero. If we consider this as initial point of the motion, we can write

u = 0

The time it takes for the ball to go down from the maximum heigth to the ground is half the total time, so

$t=\frac{1.84s}{2}=0.92 s$

And solving the formula for v, we find the final velocity:

$v=0+(-9.8)(0.92)=-9.0 m/s$

So, the final speed is 9.0 m/s.

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3 years ago

A mule is harnessed to a sled having a mass of 246 kg, including supplies. The mule must exert a force exceeding 1210 N at an an

zimovet [89]

(a) 1800 N

The equation of the forces along the vertical direction is:

$F sin \theta + N - mg = 0$

where

$F sin \theta$ is the component of the applied force along the vertical direction

N is the normal force on the sled

mg is the weight of the sled

Substituting:

F = 1210 N

m = 246 kg

$\theta = 30.3^{\circ}$

We find N:

$N=mg-F sin \theta = (246)(9.8)-(1210)(sin 30.3^{\circ})=1800 N$

(b) 0.580

The equation of the forces along the horizontal direction is:

$F cos \theta - \mu_s N = 0$

where

$F cos \theta$ is the horizontal component of the push applied by the mule

$\mu_s N$ is the static frictional force

Substituting:

F = 1210 N

N = 1800 N

$\theta = 30.3^{\circ}$

We find $\mu_s$ , the coefficient of static friction:

$\mu_s = \frac{F cos \theta}{N}=\frac{(1210)(cos 30.3^{\circ})}{1800}=0.580$

(c) 522 N

In this case, the force exerted by the mule is

$F= 6.05 \cdot 10^2 N = 605 N$

So now the equation of the forces along the horizontal direction can be written as

$F cos \theta - F_f = 0$

where

$\theta=30.3^{\circ}$

and $F_f$ is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value $\mu N$ , depending on how much force is applied in the opposite direction)