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4 years ago

A ball is thrown upward. After reaching a

Physics

1 answer:

Triss [41]4 years ago

3 0

Answer:

9.0 m/s

Explanation:

The problem can be solved by using the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

$a=g=-9.8 m/s^2$ is the acceleration of gravity

t is the time

When the ball reaches the maximum height, the velocity becomes zero. If we consider this as initial point of the motion, we can write

u = 0

The time it takes for the ball to go down from the maximum heigth to the ground is half the total time, so

$t=\frac{1.84s}{2}=0.92 s$

And solving the formula for v, we find the final velocity:

$v=0+(-9.8)(0.92)=-9.0 m/s$

So, the final speed is 9.0 m/s.

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A pair of fuzzy dice is hanging by a string from your rearview mirror. while you are accelerating from a stoplight to 28 m/s in

Lerok [7]

We can use the formula of motion in physics (2nd law od newton) in this problem:
x direction: Fsin ∅ = ma
y direction: Fcos ∅ -mg = 0
∅ is equal to sin ∅ / cos ∅ or x/y
tan ∅ = ma / mg = a /g

Applying acceleration formula:
v = vo + at ; 28 = 0 + 6a ; a = 4.67 m/s^2
∅ = tan-1 (a/g) = tan-1 (4.67/9.81) = <span>25.4 degrees.</span>

4 0

3 years ago

If f^-1(y) is the inverse of f(x) which statements must be true?

Salsk061 [2.6K]

Let us assume f(x) = 2x - 5
f⁻¹(x) = (x + 5)/2
f(f⁻¹(x)) = 2((x + 5)/2) - 5 = x
f⁻¹(f(x)) = (2x - 5 + 5)/2 = x
The domain of a function is the range of its inverse and vice versa
The range of a function is the domain of its inverse and vice versa
Therefore, statements A, B, D and E are true

6 0

4 years ago

After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 5.50 kg of

zysi [14]

Answer:

$Q = 4.40 \times 10^5 Cal$

Explanation:

Here we know that initial temperature of ice is given as

$T = 0^o C$

now the latent heat of ice is given as

$L = 80 Cal/g$

now we also know that the mass of ice is

$m = 5.50 kg$

so here we know that heat required to change the phase of the ice is given as

$Q = mL$

$Q = (5.50 \times 10^3)(80)$

$Q = 4.40 \times 10^5 Cal$

3 0

4 years ago

A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its maximum displacement from

kaheart [24]

Answer:

zero

Explanation:

In this system, only conservative forces act. Therefore, the mechanical energy, that is, the sum of the kinetic energy and the potential energy, remains constant. When the mass is at its maximum displacement from equilibrium, its potential energy is maximum, therefore, its kinetic energy is minimal, that is to say, that its instantaneous velocity at that point is zero.

6 0

4 years ago

How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius

Korvikt [17]

Answer:

<h2>The coefficient of static friction will be 0.7</h2>

Explanation:

Given data

the radius of curve= 90m

speed v= 90 km/h to m/s = (90*100)/60*60= 25 m/s

we know that the expression for the centripetal force acting on the car

$Fc= \frac{mv^2}{r}$ -------1

we also know that the expression for the frictional force between road and tire.

Ff= μmg--------2

Equating equation 1 and 2 we have

μmg= mv^2/r

μ= v^2/gr

substituting the values of speed and radius we have (assuming g= 9.81m/s^2)

μ= 25^2/9.81*90

μ= 625/882.9

μ= 0.7

4 0

3 years ago