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Angelina_Jolie [31]
3 years ago
9

Are y'all into spirituality ?

Physics
2 answers:
Afina-wow [57]3 years ago
8 0
Yeah
why are you ???
Murrr4er [49]3 years ago
8 0

Answer:

I'm christian

Explanation:

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Which describes the properties reflection, absorption, and transmission when the light is shining on the oval end of a silver sp
I am Lyosha [343]

B. It reflects a lot of light, transmits almost no light, and absorbs some light.


5 0
3 years ago
An object with little mass won't require a lot of force to move.
Anna35 [415]

Answer:

True

Explanation:

Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.

7 0
3 years ago
What is the acceleration of a 55 kg block of cement when pulled sideways with a net force of 356 N? Answer in units of m/s2.
puteri [66]
F=ma
a=F/m = 356/55 = .... m/s2
5 0
3 years ago
A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif
Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

v(t)=-gt-v_e\times \ln \frac{m-rt}{m}

v = velocity of rocket at time t

g = Acceleration due to gravity =9.8 m/s^2

v_e = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})

v(60) = 668.97 m/s

Height of the rocket = h

Velocity=\frac{Displacement}{time}

668.97 m/s=\frac{h}{60 s}

h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km

Height of the rocket be one minute after liftoff is 40.1382 km.

4 0
3 years ago
Four complete waves pass the duck in one second the frequency of this wave is
galben [10]
The frequency of a wave is the number of complete oscillations passing a given point per second.

In this case, assuming the duck is stationary, we have 4 complete waves passing the duck in one second: therefore, the frequency of the wave is
f= \frac{4}{1 s}=4 Hz
3 0
3 years ago
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