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3 years ago

Are y'all into spirituality ?

Physics

2 answers:

Afina-wow [57]3 years ago

8 0

Yeah
why are you ???

Murrr4er [49]3 years ago

8 0

Answer:

I'm christian

Explanation:

You might be interested in

Which describes the properties reflection, absorption, and transmission when the light is shining on the oval end of a silver sp

I am Lyosha [343]

B. It reflects a lot of light, transmits almost no light, and absorbs some light.

5 0

3 years ago

An object with little mass won't require a lot of force to move.

Anna35 [415]

Answer:

True

Explanation:

Heavier objects (objects with more mass) are more difficult to move and stop. Heavier objects (greater mass) resist change more than lighter objects. Example: Pushing a bicycle or a Cadillac, or stopping them once moving. The more massive the object (more inertia) the harder it is to start or stop.

7 0

3 years ago

What is the acceleration of a 55 kg block of cement when pulled sideways with a net force of 356 N? Answer in units of m/s2.

puteri [66]

F=ma
a=F/m = 356/55 = .... m/s2

5 0

3 years ago

A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif

Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

$v(t)=-gt-v_e\times \ln \frac{m-rt}{m}$

v = velocity of rocket at time t

g = Acceleration due to gravity = $9.8 m/s^2$

$v_e$ = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

$v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})$

$v(60) = 668.97 m/s$

Height of the rocket = h

$Velocity=\frac{Displacement}{time}$

$668.97 m/s=\frac{h}{60 s}$

$h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km$

Height of the rocket be one minute after liftoff is 40.1382 km.

4 0

3 years ago

Four complete waves pass the duck in one second the frequency of this wave is

galben [10]

The frequency of a wave is the number of complete oscillations passing a given point per second.

In this case, assuming the duck is stationary, we have 4 complete waves passing the duck in one second: therefore, the frequency of the wave is
$f= \frac{4}{1 s}=4 Hz$

3 0

3 years ago