You found CD from the Pythagorean theorem to be ...
... CD = √(5² -2²) = √21
Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:
... AC/AD = AB/AC
... AB = AC²/AD
... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle
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Then the area (A) is ...
... A = (1/2)bh
... A = (1/2)(12.5)(√21) ≈ 28.64 square units
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As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...
... ADC ~ CDB ~ ACB
You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.
Answer:
D one solution.
Step-by-step explanation:
It's linear. It is going to have at most 1 solution
8 + x/6 = x/6 - 4 + 5x/12 Subtract x/6 from both sides
8 = -4 + 5x/12 Add 4 to both sides
8+4 = 5x / 12 Combine
12 = 5x / 12 Multiply both sides by 12
12 * 12 = 5x * 12 / 12 Cancel
144 = 5x Divide by 5
144/5 = 5x/5
28.8 = x
First do PEMDAS
There's no parenthesis. So move on to exponent. There's also no exponents. Move on to multiplication. There it is.
12×5=60.
There's no division so now next one is addition. Hey look! There is addition.
60+55=115.
So 115 is your answer.
Lateral surface are = 2( 1/2 x 11 x 11.9) + 2( 1/2 x 9 x 12.3)
Lateral surface area = 130.9 + 110.7 = 241.6 ft²
Answer: 241.6 ft² (Answer C)
Answer:
I would say C not to sure tho