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Gnom [1K]
3 years ago
16

One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value.

how will the electrical force between the cahrges compare to the original force
it will decrease to 6 times the original force
it willnincrease to 36 times the original force
it will decrease to one-sixth the original force
it will decrease to one-thirty-sixth the original force​
Physics
2 answers:
Elanso [62]3 years ago
8 0

I just had this question on my test, the answer is C.

telo118 [61]3 years ago
5 0

Answer:

The new force will decrease to one sixth the original value.

Explanation:

It is given that,

One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value.

Let, q'_1=\dfrac{1}{3}q_1 q₁ is the charge 1

q'_2=\dfrac{1}{2}q_2 q₂ is the charge 2

Initially, the electrical force between the charges is given by :

F=k\dfrac{q_1q_2}{r^2}...........(1)

Let F' is the new force i.e.

F'=k\dfrac{q'_1q'_2}{r^2}

So,

F'=k\dfrac{\dfrac{1}{3}q_1\times \dfrac{1}{2}q_2}{r^2}

F'=\dfrac{1}{6}k\dfrac{q_1q_2}{r^2}

F'=\dfrac{1}{6}F  (from equation 1)

Hence, the new force will decrease to one sixth the original value.

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At what step in the scientific method does a scientific propose the problem that he or she wants to solve
stiv31 [10]

Answer: That would be the first step of the scientific method. After that, the scientist would research the problem and form a hypothesis

8 0
3 years ago
What is the phase of the Moon if it . . .
anzhelika [568]

Answer:

Waxing Gibbous

Third quarter

Waning Gibbous

Explanation:

If moon rises at 3:00 pm then the phase of the moon will be "Waxing Gibbous".

This is because, the moon is actually not fully illuminated but has achieved more than half of its full illumination.

If the moon is highest in the sky at sunrise then the phase of the Moon will be the "Third quarter"

This is because of the fact that at this position moon will rise at midnight, thus it will be at the highest point at the time of the sunrise.

If the moon sets at 10:00 am then the phase of the Moon is "Waning Gibbous"

This is because of the fact that at this position the Moon is moving towards becoming new Moon but at the same time,  the moon is illuminated more than its half illumination.

8 0
3 years ago
A 2000 N net force will give a car with some amount of mass an acceleration of 4 m/s2
hammer [34]

Answer:

2m/s²

Explanation:

Given parameters:

Net force on the car  = 2000N

Acceleration = 4m/s²

Unknown:

Acceleration of a car twice the mass  = ?

Solution:

Let us first find the mass of the car;

 Force  = mass x acceleration

         Mass = \frac{Force }{acceleration}  

 Mass = \frac{2000}{4}   = 500kg

 Now,

     whose mass is twice that of the car

    Mass of the new car = 2 x 500  = 1000kg

So;

  Acceleration  = \frac{Net force }{mass}  

  Acceleration  = \frac{2000}{1000}  = 2m/s²

3 0
3 years ago
WILL GIVE BRAINLY!! PLEASE HELPP
LekaFEV [45]

The purpose of the machine is to leverage its mechanical advantage such that the force it outputs to move the heavy object is greater than the force required for you to input.

But there's no such thing as a free lunch! When you apply the conservation of energy, the work the machine does on the object will always be equal to (in an ideal machine) or less than the work you input to the machine.

This means that you will apply a lesser force for a longer distance so that the machine can supply a greater force on the object to push it a smaller distance. That is the trade-off of using the machine: it enables you to use a smaller force but at the cost of having to apply that smaller force for a greater distance.

The answer is: The work input required will equal the work output.

8 0
3 years ago
You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The
AnnZ [28]

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

6 0
3 years ago
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