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Charra [1.4K]
3 years ago
8

The speed of sound through air is approximately 340 m/sec. What is the wavelength of a sound wave with a frequency of 706 Hz? Ro

und to the nearest hundredth
Physics
1 answer:
cestrela7 [59]3 years ago
7 0

Answer:

Wavelength  = 0.48 m (Approx)

Explanation:

Given:

Speed of sound = 340 m/s

Frequency = 706 hz

Find:

Wavelength

Computation:

Wavelength  = Speed of sound / Frequency

Wavelength  = 340 / 706

Wavelength  = 0.48 m (Approx)

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You are designing a flywheel. It is to start from rest and then rotate with a constant angular acceleration of 0.200 rev/s^2. Th
Rama09 [41]

Answer:

 I = 8.75 kg m

Explanation:

This is a rotational movement exercise, let's start with kinetic energy

        K = ½ I w²

They tell us that K = 330 J, let's find the angular velocity with kinematics

      w² = w₀² + 2 α θ

as part of rest w₀ = 0

      w = √ 2α θ

let's reduce the revolutions to the SI system

      θ = 30.0 rev (2π rad / 1 rev) = 60π rad

let's calculate the angular velocity

      w = √(2  0.200  60π)

      w = 8.683 rad / s

we clear from the first equation

        I = 2K / w²

let's calculate

        I = 2 330 / 8,683²

        I = 8.75 kg m

4 0
3 years ago
What is a step down transformer
ratelena [41]

Answer:

A step down transformer is a device that can be connected to the switch and the appliance. There are two types of transformers that you should know about: step up and step down transformers. Step up transformers generally produce a higher output voltage than the input voltage.

Explanation:

7 0
3 years ago
Hi there, it is your average pathetic Junior. Anyways, I need help on 8&9 ASAP, this assignment is beyond overdue but hey wh
zheka24 [161]

Answer:

a) -31.36 m/s

b) 50.176 m

Explanation:

<h2>a) Velocity of the bag</h2>

This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:

V_{f}=V_{o} +a.t  (1)

Where:

V_{f} is the final velocity of the supply bag

V_{o}=0 is the initial velocity of the supply bag (we know it is zero because we are told <u>it was "dropped", this means it goes to ground in free fall</u>)

a=g=-9.8m/s^{2} is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)

t=3.2s is the time

Knowing this, let's solve (1):

V_{f}=0+(-9.8m/s^{2})(3.2s)  (2)

Hence:

V_{f}=-31.36m/s  Note the negative sign is because the direction of the bag is downwards as well.

<h2>b) Final height of the bag</h2>

In this case we will use the following equation:

y=V_{o}t-\frac{1}{2}gt^{2} (3)

Where:

y is the distance the bag has fallen

V_{o}=0 remembering <u>the bag was dropped</u>

g=-9.8m/s^{2} is the acceleration due gravity (downwards)

t=3.2 s is the time

Then:

y=-\frac{1}{2}gt^{2} (3)

y=-\frac{1}{2}(-9.8m/s^{2})(3.2)^{2} (4)

Finally:

y=50.176 m

4 0
3 years ago
PLEASE HELP!!!!!!
elena-s [515]

Answer:For this equation you would have to take the numerator and multiply with the other one, which would leave you with 24/80 and if you want the simplified version it would be 3/10, hope this helps! :)

Explanation:

4 0
3 years ago
a. How high did the car climb up the hill after bouncing? Did it go higher lower or the same height as the drop position?
weeeeeb [17]
THe answer is the car went higher
8 0
3 years ago
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