All categories

3 years ago

How do you know something has moved even if you didn't see the object move?

Physics

1 answer:

Anettt [7]3 years ago

6 0

Answer:Use relative position.

Explanation:

An object is moving if its position

relative to a fixed point is changing.

Remember, a book on a desk does not seem to be moving, but if you put it relative to the sun, it is moving at 30 km per second. Look for relativity in motion.

You might be interested in

A French submarine and a U.S. submarine move toward each other during maneuvers in motionless water in the North Atlantic. The F

Mandarinka [93]

Answer:

$f_{U}= 1019.72hz$

Explanation:

From the equation we are told that:

Velocity of French sub $V_{U}= 43.00km/h$

Velocity of U.S. sub at $V_{F}|=64.00 km//h$

French Wave Frequency $F_{F}=1000Hz$

Velocity of wave $V_{s}=5470 km/h$

Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by

Doppler effect

$f_{U} = \frac{ f_F (vs + v_{U})}{(v_s - v_F) }$

$f_{U}= \frac{ 1000 x ( 5470+64)}{(5470-43)}$

$f_{U}= 1019.72hz$

5 0

3 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. If a ray of white light enters the wat

kobusy [5.1K]

Answer:

Angle of refraction for red light is $43.01^{\circ}$

Angle of refraction for blue light is $42.68^{\circ}$

Explanation:

It is given refractive index for red light is $\mu _{red}=1.331$

Refractive index of blue light $\mu _{blue}=1.340$

Angle of incidence $i=65.30^{\circ}$

According to law of refraction $\mu =\frac{sini}{sinr}$

For red light $1.331 =\frac{sin65.30^{\circ}}{sinr}$

$1.331 =\frac{0.908}{sinr}$

$sinr=0.682$

$r=43.01^{\circ}$

Therefore angle of refraction for red light is $43.01^{\circ}$

Similarly for blue light $1.340 =\frac{sin65.30^{\circ}}{sinr}$

$1.340 =\frac{0.908}{sinr}$

$sinr=0.677$

r = $42.68^{\circ}$

Therefore angle of refraction for blue light is $42.68^{\circ}$

6 0

3 years ago

Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equatio

yarga [219]

Answer:

m(P4) = 46.175 (grams)

m (KClO3) = 149 (grams)

Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).

6 0

2 years ago

Ursula has something that she thinks is a metal. If she places it above the flame from a candle, it should...? A. quickly get ve

AlladinOne [14]

The answer would be C since metals have electrons that help in heating up the metal

5 0

3 years ago

Read 2 more answers

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

Nesterboy [21]

Answer:

A.) 1372 N

B.) 1316 N

C.) 1428 N

Explanation:

Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:

a. The load moves downward at a constant velocity

At constant velocity, acceleration = 0

T - mg = ma

T - mg = 0

T = mg

T = 140 × 9.8

T = 1372N

b. The load accelerates downward at a rate 0.4 m/s??

Mg - T = ma

140 × 9.8 - T = 140 × 0.4

1372 - T = 56

-T = 56 - 1372

- T = - 1316

T = 1316N

C. The load accelerates upward at a rate 0.4 m/s??

T - mg = ma

T - 140 × 9.8 = 140 × 0.4

T - 1372 = 56

T = 56 + 1372

T = 1428N

8 0

4 years ago