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ivolga24 [154]
3 years ago
12

4. A cylindrical tube has a length of 14.4cm and a radius of 1.5cm and is filled with a colorless gas. If the density of the gas

is known to be 0.00123g/cm', what is the mass of the gas in the tube in mg?​
Physics
1 answer:
professor190 [17]3 years ago
5 0

Answer:

Mass, m of gas is 0.2504 grams.

Explanation:

First, we need to solve for the volume of the cylindrical tube.

Volume of cylinder is given by the formula;

V = 2\Pi r^{2}h

Where, V represents volume.

π represents pie

r represents radius.

h represents height or length.

Given the following data;

Radius, r = 1.5cm

Length, h = 14.4cm

Density, d = 0.00123g/cm³

Substituting into the equation;

V = 2 * 3.142 * (1.5)^{2}14.4

V = 2 * 3.142 * 2.25 * 14.4

V = 203. 6016

Therefore, the volume of the cylindrical tube is 203. 6016cm³

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

Density = \frac{mass}{volume}

Mass = density  *  volume

Substituting into the equation, we have;

Mass = 0.00123 * 203. 6016

Mass = 0.2504g.

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At a department store, you adjust the mirrors in the dressing room so that they are parallel and 6.2 ft apart. You stand 1.8 ft
barxatty [35]

Answer:

<em>a) 3.6 ft</em>

<em>b) 12.4 ft</em>

Explanation:

Distance between mirrors = 6.2 ft

difference from from the mirror you face = 1.8 ft

a) you stand 1.8 ft in front of the mirror you face.

According to plane mirror rules, the image formed is the same distance inside the mirror surface as the distance of the object (you) from the mirror surface. From this,

your distance from your first "front" image = 1.8 ft + 1.8 ft = <em>3.6 ft</em>

b) The mirror behind you is 6.2 - 1.8 = 4.4 ft behind you.

the back mirror will be reflected 3.6 + 4.4 = 8 ft into the front mirror,

the first image of your back will be 4.4 ft into the back mirror,

therefore your distance from your first "back" image = 8 + 4.4 = <em>12.4 ft</em>

8 0
3 years ago
75% of what number is 27? EXPLAIN
zmey [24]
75 percent (calculated percentage %) of what number equals 27? Answer: 36.
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3 years ago
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Find the cost of excavating a space 84 ft long, 42 ft wide, and 9 ft deep at a cost of $39/yd3. (simplify your answer completely
m_a_m_a [10]

The cost of excavating a space of 84 ft long, 42 ft wide, and 9 ft deep is $45864

Information about the problem:

  • Space long= 84 ft
  • Space wide= 42 ft
  • Space deep= 9 ft
  • Cost by yard3 = $39/yd3
  • Total cost= ?

To solve this problem, we have to state the equation using the information of the problem:

Calculating the volume of the total space:

space volume = space long * space wide * space deep

space volume = 84 ft * 42 ft * 9 ft

space volume = 31752 ft3

By converting the volume from ft3 to yd3, we have:

31752 ft3 * (0,037037 yd3 / 1 ft3) = 1176 yd3

Calculating the cost of excavating the volume space:

Total cost = space volume * cost by yard3

Total cost = 1176 yd3 * $39/yd3

Total cost = $45864

<h3>What is volume?</h3>

It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.

Learn more about volume at: brainly.com/question/12628341

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4 0
1 year ago
1. How do galaxies change over time? 2. How are galaxies created? 3. How was Hubble important to our understanding of galaxies?
VashaNatasha [74]

Hi!


1. Galaxies are constantly evolving with time, and one manner that they do this is that they change their rotation. This is apparent from the knowledge we have of initially formed galaxies which are spiral like in the beginning, but over time transform into what seems like smooth, barren disks. Another difference is that some galaxies are younger than others, and the age difference is observed with younger galaxies having a higher number of stars that are also comparatively brighter, which makes these galaxies look blue. Older galaxies contain older stars, and older stars are seen to give off red light, which is why these galaxies seem red. Galaxies also undergo various physical and chemical changes, and older galaxies are more structured.


2. Galaxies are brought into formation with the major factor being gravity. The force of gravity is responsible for attracting various stars, collapsing gas, dust clouds and other dark matter into a structured body. Over time the organization becomes more defined. So basically, a galaxy starts off as clouds of dust and stars in space, which come into proximity with other similar clouds, and their subsequent interactions shape the structure of the galaxy.


3. Edwin Hubble, also known as the 'pioneer of distant stars', has contributed to out understanding of galaxies in that he was the first person to prove the existence of galaxies other than the Milky Way, through his studies on spiral nebulae (which were formerly thought to be clouds of dust and gas, but were actually galaxies). He also established the relationship of red shift of a galaxy (recession velocity) and the distance of the galaxy from the Earth - a directly proportional relationship, which is known as the Hubble's Law.


4. The Milky Way is found to be considerably larger, about ten times, than the average dwarf galaxy being 100,000 light years across in diameter. The Milky Way is home to 200 billion stars, and with the capacity (dust and gas) to give rise to billions more. The Milky Way is the biggest galaxy in the Virgo Supercluster, and is relatively old in comparison with most other galaxies within the universe.


5. Dark matter and gravity play a role in determining the structure of the galaxy and influences the environment over time. Dark matter contributes to the mass of the galaxy, and this affects the spin of the galaxy. The more the mass of a galaxy (or more massive a galaxy) the greater would be its rotation. Gravity is the acting force that holds the components of galaxy in place, such as the dust clouds, colonies of star, gas and dark matter. Gravity influences the structure in that it exerts and inward pull on the stars, resulting in the spiral arm structure of a galaxy, which over time tends to be more eclipse like.


Hope this helps!

7 0
3 years ago
water is pumped from a stream at the rate of 90kg every 30s and sprayed into a farm at a velocity of 15m/s. Calculate the power
nikitadnepr [17]

Answer:

340 W

Explanation:

Power = change in energy / change in time

P = ΔKE / Δt

P = ½ mv² / Δt

P = ½ (90 kg) (15 m/s)² / (30 s)

P = 337.5 W

Rounded to 2 significant figures, the power is 340 W.

7 0
3 years ago
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