Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:

where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:

<u>Thrust = 200 N</u>
Answer:
E=0.036 V/m
Explanation:
Given that
Resistivity ,ρ=2.44 x 10⁻⁸ ohms.m
d= 0.9 mm
L= 14 cm
I = 940 m A = 0.94 A
We know that electric field E
E= V/L
V= I R
R=ρL/A
So we can say that
E= ρI/A
Now by putting the values

E=0.036 V/m
Explanation:
Total Internal Reflection (TIR) is a phenomenon in optics, by which light experiences complete reflection at an interface between two media.
In the figure i > © experience total internal reflection
<span><span>3,730 W is equal to about 5 horsepower. (4.9982 hp)</span></span>
Answer:
C = 4,174 10³ V / m^{3/4}
, E = 7.19 10² / ∛x, E = 1.5 10³ N/C
Explanation:
For this exercise we can calculate the value of the constant and the electric field produced,
Let's start by calculating the value of the constant C
V = C
C = V / x^{4/3}
C = 220 / (11 10⁻²)^{4/3}
C = 4,174 10³ V / m^{3/4}
To calculate the electric field we use the expression
V = E dx
E = dx / V
E = ∫ dx / C x^{4/3}
E = 1 / C x^{-1/3} / (- 1/3)
E = 1 / C (-3 / x^{1/3})
We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E
E = 3 / C (0- (-1 / x^{1/3}))
E = 3 / 4,174 10³ (1 / x^{1/3})
E = 7.19 10² / ∛x
for x = 0.110 cm
E = 7.19 10² /∛0.11
E = 1.5 10³ N/C