The time of motion of the track star is determined as 0.837 s.
<h3>Time of motion of the track star</h3>
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
- T is time of motion
- g is acceleration due to gravity
- θ is angle of projection
T = (2 x 12 x sin20)/9.8
T = 0.837 s
Learn more about time of motion here: brainly.com/question/2364404
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Answer:
The distance between the camera and the rock is 836.6 cm
Explanation:
A right triangle is formed where the hypotenuse (h) is the distance between the rock and the camera. One of the leg (l) is the distance between the camera and the surface. The angle between the hypotenuse and this leg is α = 90° - 13.69° = 76.31°. By definition:
cos α = adjacent/hypotenuse
cos(76.31) = 198.0/h
h = 198.0/cos(76.31)
h = 836.6 cm
The speed of the carts descent will increase? Not quite sure what you’re asking.
Answer: v = 11 m/s
Explanation:
If we ASSUME that the road is horizontal, not banked
The maximum friction force available is μmg
This will need to supply all of the required centripetal force
mv²/R = μmg
v = √(μgR) = √(0.28(9.8)(45)) = 11.1121...≈ 11 m/s
