Question

The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth of 9 m. (Round the final answer to the nearest whole number.)

Answer 1

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

$\frac{P_{1} }{\\P_2}$= $\frac{density * g * h_1}{density * g * h_2}$

So $\frac{39}{P_2}$= $\frac{3}{9}$

Or P₂= 39 * 3 = 117 kPa