Answer:
World languages__
Explanation:
A selective college usually requires more years of ___World languages__ than a high school requires. College graduates would look for jobs after college, they might have to travel to different countries. So, educating them about different language would give them a competitive edge to them. Moreover, in the age of globally integrated business community, knowing an extra language could work as cherry top on the cake.
Answer:
(a) The spring constant is 426N/m
(b) The mass is 5.65kg
Explanation:
(a) Energy stored in the spring (E) = 3.6J, extension (e) = 0.13m
E = 1/2Ke^2
3.6 = 1/2 × K × 0.13^2
K (spring constant) = 3.6×2/0.0169 = 426N/m
(b) F = Ke = 426 × 0.13 = 55.38N
Assuming the maximum acceleration (a) is 9.8m/s^2
Mass (m) = F/a = 55.38/9.8 = 5.65kg
Work = (force) x (distance)
Power = (work) / (time)
Knowing force, distance, and time, it looks like
you can calculate both <em>work and power</em>.
But that's not all !
-- <u>Speed</u> = (distance) / (time)
-- <u>Impulse</u> = change in momentum = (force) x (time)
Answer:
Keq = 2k₃
Explanation:
We can solve this exercise using Newton's second one
F = m a
Where F is the eleatic force of the spring F = - k x
Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement
F + F = m a
k₃ x + k₃ x = m a
a = 2k₃ x / m
To find the effective force constant, suppose we change this spring to what creates the cuddly displacement
Keq = 2k₃
