Explanation:
It is given that,
Electric field strength, E = 20,000 N/C
Spacing between parallel-plate capacitor, d = 1 mm = 0.001 m
Initial velocity of electron, u = 0
Let v is the electron’s speed when it reaches the positive plate. The force acting on the electron is :
Also,
Using third equation of motion as :
v = 2649528.2599 m/s
or
So, the velocity of the electron when it reaches the positive plate is . Hence, this is the required solution.
Answer:
The work done is and it is negative because the exterior is doing work on the gas.
The value of the heat flow is and is directed out of the gas, as this is being cooled and compressed.
Explanation:
The work done by the gas can be written as
and all the data is given in the problem, so
is the work necessary to compress the gas in the cylinder, wich is negative because the exterior is doing work on the gas.
Now, from first law of thermodynamics, we have that
<em>where is the internal energy difference,
is the calculated work, and
is the heat flow that we wish to know</em>, then
And the direction of the heat flow is outside of the gas, as it is being cooled and compressed.
Finally, it doesn't matter whether the gas is ideal or not, because we never use the Ideal Gas hypotesis, that , and
is constant.
Answer:
Explanation:
We have here a simple harmonic motion, so the equation of the position in this motion is:
(1)
A: Amplitude
ω: angular frequency
φ: phase constant
If we take the derivative of x with respect to t from (1), we can find the velocity equation of this motion:
(2)
Let's evaluate (1) and (2) in t=0.
(3)
(4)
Dividing 4 by 3 we have:
Now, using (3) we can find the amplitude.
I hope it helps!