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erastova [34]
3 years ago
15

A wheel starts from rest and rotates with a constant angular acceleration about a fixed axis. It completes the first revolution

6.0 s after it started. How long after it started will the wheel complete the second revolution?
Physics
1 answer:
Len [333]3 years ago
6 0

Answer:

After 8.5 s

Explanation:

We can use the equivalent suvat equation for rotational motions to find the angular acceleration of the wheel:

\theta = \omega_i t + \frac{1}{2}\alpha t^2

where:

\theta = 2\pi rad is the angular displacement covered during the first 6.0 s (the angle corresponding to one revolution)

\omega_i=0is the initial angular velocity

\alpha is the angular acceleration

t = 6.0 s is the time

Solving for  \alpha,

\alpha = \frac{2\theta}{t^2}=\frac{2(2\pi)}{6.0)^2}=0.349 rad/s^2

Now we want to find instead the time t after which the wheel has completed two revolutions, so the time t at which

\theta = 4 \pi

Using again the same equation as before and solving for t, we find:

t=\sqrt{\frac{2\theta}{\alpha}}=\sqrt{\frac{2(4\pi)}{0.349}}=8.5 s

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an engine has been design to work between source and the sink at temperature 177 degree Celsius and 27 degree Celsius respective
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<u>Given data</u>

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

                We know that, efficiency (η) = Net work done ÷ Heat supplied

                                                           η =   W ÷ Q₁  

                                                           W = η × Q₁

               First determine the efficiency ( η ) = ?

                                Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

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               Now, Work done is W = η × Q₁

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<em>Work done by the engine is 1188 J</em>

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