Answer:
F = 33.12 N
Explanation:
given,
first force = 15 N is oriented at 58.0° counterclockwise
second force = (−19.0 N,18.5 N)
x-component of first force = 15 cos 58.0° = 7.95 N
y-component of second force = 15 sin 58.0° = 12.72 N
second component
now,
F netx = 7.95 - 19 = -11.05 N
F nety = 12.72 + 18.5 = 31.22 N
F = 33.12 N
θ = -70.51°
Answer:
The power transmitted to the pulley is 0.0455 hp.
Explanation:
Given;
mass attached to the rope, m = 5 lb
radius of the pulley, r = 3 in
constant rate of fall of the mass, v = 5 ft/s
acceleration due to gravity, g = 32.2 ft/s²
1 lbf = 32.2 lb.ft/s²
The power transmitted to the pulley is calculated as;
P = Fv
P = (mg)v
in horse power, the power transmitted is calculated as;
Therefore, the power transmitted to the pulley is 0.0455 hp.