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Brums [2.3K]
3 years ago
13

Two small objects are suspended from threads. When the objects are moved close together, they attract one another. What of the f

ollowing could produce this result?a. On object is positively charged and the other is negatively charged.b. One object is positively charged and the other conductor is uncharged.c. One object is negatively charged and the other conductor is uncharged.d. All of the above could result in an attraction.
Physics
1 answer:
creativ13 [48]3 years ago
4 0

Answer:d

Explanation:

All the given situations are possible because

(a)When particles are oppositely charged then they attract each other

(b)One is Positively charged and other is uncharged: Charged particle will induce charges of opposite nature to attract the other particle

(c)Negatively charged particles will induce the positive charge in the uncharged particle to attract the initially uncharged particle.

                 

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do not obey ohm's law so it's a I believe

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3 years ago
A net force, the magnitude of which is 3800 N, accelerates a 1260-kg vehicle for 10.0 s. The vehicle travels 50.0 m during this
Novay_Z [31]

Answer:

SEE EXPLANATION

Explanation:

p =  \frac{fd}{t}  \\ where \: \\p  = power \\  f = force \\ d = distance \\ and \: t = time \\  \\ p =  \frac{3800 \times 50}{10}  \\ p =  \frac{190000}{10}  \\ p = 19000w

7 0
3 years ago
These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

6 0
3 years ago
Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons a
dsp73

Answer:

E=576.5V/m

Explanation:

From the question we are told that:

Length l=56.0cm=0.56m

Distance apart d=7.0mm=0.007m

Electron Transferred n=10^{-10}

Therefore

Total Charge

Since Charge on each electron is

e=1.602*10^{-19}

Therefore

T=1.602*10^{-19} *10^{10}

T=1.602*10^{-9}

Generally the equation for Charge density is mathematically given by

\rho=T/A

Where

Area

A=0.56*0.56

A=0.3136

Therefore

\rho=1.602*10^{-9}/0.3136

\rho=5.10*10^{-9}

Generally the equation for Electric Field in the capacitor is mathematically given by

E=\frac{\rho}{e_0}

E=\frac{5.10*10^{-9}}{8.85x10{-12}}

E=576.5V/m

8 0
3 years ago
How do the units of work and power compare?
ki77a [65]

Answer:

Option (d) is correct.

Explanation:

Work done is given by :

W = Fd, where F is force and d is displacement

Unit of work done :

The SI unit of force is Newton (N) and that of displacement is meter (m). So, the unit of work done is N-m. It is call Joule. It means that the unit of work done is Joule.

Power is given by rate at which the work is done. It is given by :

P = W/t, W is work done and t is time

Unit of power:

Unit of work is Joule (J) and that of time is second (s). It means that the unit of power is Watt and it is equal to Joule/second

Hence, the correct option is (d) "The unit for work is a joule. The unit for power is a watt, which is a joule per second".

7 0
2 years ago
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