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4 years ago

The term "accuracy" best refers to which of the following?

Physics

2 answers:

iVinArrow [24]4 years ago

8 0

D: how close a measurement is to an accepted value for the measurement.

vladimir2022 [97]4 years ago

3 0

Answer: d. how close a measurement is to an accepted value for the measurement

Explanation:

Accuracy can be define as the quality or state of some measurement being correct depending upon the measurement, specific conformations and calculations. It refers to the closeness of the measurement to a define specific or acceptable value. It is the degree of correctness of a particular value obtain after the measurement.

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An object moves in a circle with a period of 0.025 hours. What is its frequency in Hz?

Sedaia [141]

Answer:

40 Hz

Explanation:

f = 1/T = 1 / 0.025 = 40 Hz

7 0

3 years ago

During an ultrasound, sound waves are sent by a transducer through muscle tissue at a speed of 1300 m/s. Some of the sound waves

alina1380 [7]

$2.3 \times 10^{-5} \text { seconds }$ is the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted

Option C

<u>Explanation:</u>

Given data:

speed, v = 1300 m/s

distance, d = 3.0 cm = $3.00 \times 10^{-2} \mathrm{m}$

We need to calculate the time taken by the transducer to detect the reflected waves from the metal fragment after they were first emitted.

As we know, the velocity is the ratio of distance and the time travelled by an object. The equation form is given by,

$\text {velocity, } v=\frac{\text {distance }(d)}{\text {time}(t)}$

By applying the given values to the above equation, we get

$1300=\frac{3.00 \times 10^{-2}}{t}$

$t=\frac{3.00 \times 10^{-2}}{1300}=0.002307 \times 10^{-2}=2.3 \times 10^{-5} \text { seconds }$

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4 years ago

10. Find the mass density of a ball with 22.0 g and a radius of 0.875 cm.

Ede4ka [16]

Answer:

Mass (m) = 22.0 g

Radius (r) = 0.875 cm

Density (d) = ?

First find ( volume) ;

$v = \frac{4}{3} \pi \: {r}^{3} \\ \\ v = \frac{4}{3} \times 3.14 \times ( {0.875)}^{3} \\ \\ v = \frac{4}{3} \times 3.14 \times 0.66992187 \: {cm}^{3} \\ \\ v = 2.8 \: {cm}^{3}$

$Density = \frac{mass}{volume} \\ \\ d = \frac{m}{v} \\ \\ d = \frac{22}{2.8} \\ \\ d = 7.857 \: \frac{g}{ {cm}^{3} }$

I hope I helped you^_^

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3 years ago

QUESTION 6

Daniel [21]

Question 7 is false

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3 years ago

Read 2 more answers

What is hard but flexible structure is found in the nose and ears

avanturin [10]

<span>Cartilage is the hard but flexible structure found in pieces of your nose and ears. It is similar to bone, but allows for flexibility and movement. When looking at skeletons, you'll notice that they don't have a nose or ears, because cartilage deteriorates much faster than bone. Cartilage is also found in elsewhere in the animal kingdom--the skeletal structure of a shark is made primarily from cartilage!</span>

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3 years ago