Answer:
PE = 58.8,J
Explanation:
The potential energy at the top of ramp1 can be found by the application of the formula PE = mgh
Where PE =potential energy
m = mass of block = 2kg
g = acceleration due to gravity = 9.80m/s²
h = height of the top of the ramp from its bottom where the block is initially positioned = 3m
PE = 2×9.8×3 = 58.8J
<span>C. Travel toward the beach faster</span>
in a state of mind that prevents normal perception, behavior, or social interaction; seriously mentally il
Answer:
1. 8437500 N
2. The force between the two charges is attractive.
Explanation:
1. Determination of the force between the two charges.
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
Distance apart (r) = 80 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 2 × 3 / 80²
F = 5.4×10¹⁰ / 6400
F = 8437500 N
Thus, the force of attraction between the two charges is 8437500 N
2. From the question given, the charges are:
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
We understood that like charges repels while unlike charges attract. Since the two charges (i.e –2 C and 3 C) has opposite signs, it means they will attract each other.
Thus the force between them is attractive.
