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mrs_skeptik [129]
3 years ago
13

How many valence electrons would be used in drawing the Lewis Structure CF4?

Chemistry
2 answers:
g100num [7]3 years ago
6 0
It’s 32
Make it a brainliest answer
Elis [28]3 years ago
3 0

Answer:

32

Explanation:

You have 7 valance electrons in fluorine, and you have 4 of them. 7*4=28. Then, you have 4 valance electrons on carbon. So 28+4=32

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57.0 is it rounded to three sig figs. You count three spaces then round from there, which would be the zero and you would round down because the four is there.
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What’s my resting energy????
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3 years ago
WILL GIVE BRAINLIEST!! Determine the volume of a container that holds 2.4 mol of gas at STP.
kykrilka [37]

Answer:

2.4 mol x 22.4 liter = 53.76 liters

1 mole

Explanation:

5 0
3 years ago
2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g)a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of
Ira Lisetskai [31]

Answer:

a. 167 mL.

b. 39.3 %.

Explanation:

Hello!

In this case, for the undergoing chemical reaction, since 45.0 g of aluminum react, based on the 2:3 mole ratio with sulfuric acid, we can compute the required moles  as shown below:

n_{H_2SO_4}=45.0gAl*\frac{1molAl}{27.0gAl} *\frac{3molH_2SO_4}{2molAl} =2.50molH_2SO_4

Next, since the molarity of a solution is computed based on the moles and volume (M=n/V), we can compute the required volume of sulfuric acid as shown below:

V=\frac{n}{M}=\frac{2.50mol}{15.0mol/L}=0.167L

That in mL is 167 mL.

Moreover, for the percent yield, we compute the grams of aluminum sulfate that are produced based on the required 2.50 moles of sulfuric acid:

m_{Al_2(SO_4)_3}=2.50molH_2SO_4*\frac{1molAl_2(SO_4)_3}{3molH_2SO_4}*\frac{342.15gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=285.13gAl_2(SO_4)_3

Therefore the percent yield is:

Y=\frac{112g}{285.13g}*100\%\\\\Y=39.3\%

Best regards!

6 0
3 years ago
What is the mass of an object accelerating at 10 m/s2 when a force of 10 N is applied?
Alex Ar [27]

Answer:

Anaesthesia & Intensive Care Medicine

Volume 6, Issue 9, 1 September 2005, Page 294

Force, mass and acceleration

Author links open overlay panelPhilDalrympleaRichardGriffithsb

https://doi.org/10.1383/anes.2005.6.9.294

Get rights and content

Abstract

Force, mass and acceleration are everyday words but often used inaccurately. Force is a physical influence, which when applied to an object causes it to accelerate in the direction from which it was applied. Mass is the amount of matter in an object and is expressed in kilograms. Acceleration is the rate of change of velocity of an object in the same straight line of the unbalanced force. When forces become balanced, there is no net force and therefore no movement. Newton’s second law links these three terms and concerns the effect that an unbalanced force has on the motion of an object. It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s2). Thus, an object of constant mass accelerates in proportion to the force applied. Gravity is the variable force of attraction between any two objects. All matter possesses gravitational ‘pull’ towards other matter. The amount of gravity between two objects is dependent on their mass and the distance between their centres. The word ‘weight’ in its proper context refers to the downward vertical force exerted on an object as a result of the earth’s gravity. An object with greater mass is therefore subjected to a greater gravitational force (i.e. it has greater weight).

7 0
3 years ago
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