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tigry1 [53]
2 years ago
9

A(n) _____ may be defined as a compound which contributes hydroxide ions or increases the OH- concentration when dissolved in wa

ter.
salt
base
ester
acid
Chemistry
2 answers:
erica [24]2 years ago
6 0

Answer:

Base

Explanation:

Bases on dissolving with water release hydroxide ions

Take a example of Sodium hydroxide

  • NaOH+H_2O-->Na_0+OH-
yulyashka [42]2 years ago
5 0

Answer:I think base

Explanation:

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Enter your answer in the provided box. Liquid methanol (CH3OH) can be used as an alternative fuel in pickup and SUV engines. An
andreyandreev [35.5K]

Answer: E=∆H*n= -40.6kj

Explanation:

V(CO) =15L=0.015M³

P=11200Pa

T=85C=358.15K

PV=nRT

n=(112000×0.015)/(8.314×358.15)

n(Co)= 0.564mol

V(Co)= 18.5L = 0.0185m³

P=744torr=98191.84Pa

T= 75C = 388.15k

PV=nRT

n= (99191.84×0.0185)/(8.314×348.15)

n(H2) = 0.634mol

n(CH30H) =1/2n(H2)=1/2×0.634mol

=0.317mol

∆H =∆Hf{CH3OH}-∆Hf(Co)

∆H=-238.6-(-110.5)

∆H = 128.1kj

E=∆H×n=-40.6kj.

3 0
3 years ago
4. How many atoms are there in 4 moles<br> of sulfur?
jekas [21]

Answer:

32.065 g/mol times 4

3 0
3 years ago
How many grams of Na2SO4 are theoretically produced when excess NaCl reacts with 400 grams of H2SO4
Gnom [1K]

Answer:

335.35 grams

Explanation:

Convert grams of H2SO4 to moles and get 4.08 moles.

Using stoichiometry, the chemical equation tells us that for every mole of H2SO4, one mole of Na2SO4 is produced.  This means that, theoretically, you should get 4.08 moles.

Convert moles to grams and get 335.34 g.

However, if you were to actually perform this reaction, you would get less than the theoretical value.

Hope this helps! <3

3 0
3 years ago
What is the chemical formula for fluoride?
valentinak56 [21]

Answer:b

Explanation:

3 0
3 years ago
Read 2 more answers
(r)-2-butanol reacts with potassium dichromate (k2cro4) in aqueous sulfuric acid to give a (c4h8o). treatment of a with sodium b
weqwewe [10]
Potassium dichromate reacts with sulfuric acid to form chromic acid, H₂CrO₄ which is a very strong oxidizing agent. The secondary alcohol, (<em>R</em>)-2-butanol will be oxidized in the presence of chromic acid, but it can only be as oxidized as far as the ketone, which is the product shown, 2-butanone.

Sodium borohydride is a reducing agent that will reduce a ketone or aldehyde to an alcohol. When sodium borohydride reacts with 2-butanone, it reduces it to 2-butanol. However, the alcohol is no longer chiral as it was in the beginning since the sodium borohydride can add a hydride to either face of the carbonyl, which results in a racemic mixture of alcohols. This explains why the product has the same refractive index and boiling point as (<em /><em>R</em>)-2-butanol, however, the product formed would no longer be optically active.

5 0
3 years ago
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