K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2
So, option B is your answer!
Hope this helps!
This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400 I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
Resistance per 1000 feet for gauge 14 wire is given as
R = 2.525 ohm
now if wire is of length 50 feet only then the resistance is given as


now if 11 A current flows through the wire then the voltage drop is given by ohm's law



so most appropriate answer in given options is
A. 1.8 Volts
All of the above..........
Answer:
111.6 g
Explanation:
Given
m + M = 2.58 / 9.8
= 0.2632 kg
When the can of fruit juice is balance from scale , we get following relation
M x ( 50 - 21.2 ) = m x 21.2 ( balancing the torque due to weight of scale and can about the balancing point )
M x 28.8 = 21.2 m
= 21.2 ( 0.2632 - M )
= 5.58 - 21.2 M
M ( 28.8 + 21.2 ) = 5.58
M = .1116 kg
= 111.6 g