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Sphinxa [80]
3 years ago
11

A researcher’s background can influence the ____________ of experimental results.

Physics
1 answer:
arsen [322]3 years ago
7 0
Interpretation ? How would a biologist try to interpret results of an astrophysics experiment compared to an astrophysicist ?
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An object with a temperature of 0 Kelvin would not emit radiation.<br> a. True<br> b. False
dem82 [27]
That's true. 
Radiation always carries energy. 
An object at 0 K doesn't have any.
5 0
3 years ago
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Do heavier objects fall more slowly than lighter objects?
aksik [14]
Think of it like this, gravity has to pull harder on the heavier object to make them fall at the same rate , but doesn't have to pull as hard for the lighter object , thus is why sometimes heavier objects fall faster then lighter ones
8 0
4 years ago
How are electromagnetic waves different from sound or water waves?
Annette [7]

Explanation:

Electromagnetic waves are different from sound or water waves in such a way that water and sound waves are called mechanical waves that requires a material medium for their propagation.

Electromagnetic waves do no require a material medium for propagation.

  • Electromagnetic waves are carried or transported by radiation and this can be passed through vacuums and different other materials.
  • But mechanical waves such as water and sound waves requires a material medium for their propagation.
  • They cannot pass through a vacuum.
8 0
3 years ago
A tennis ball of mass 44.0 g is held just above a basketball of mass 594 g. With their centers vertically aligned, both are rele
ZanzabumX [31]

Answer:

u = 4.6 m/s

h = 8.01 m

Explanation:

Given:

Mass of the tennis ball, m = 44.0 g

Mass of the basket ball, M = 594 g

Height of fall, h = 1.08m

Now,

we have

u^2-u'^2 = 2as

where, s = distance = h

a = acceleration

u = final speed before the collision

u' = initial speed

since it is free fall case

thus,

a = g = acceleration due to gravity

u' = 0

thus we have

u^2-0^2 = 2\times9.8\tiimes1.08

or

u = \sqrt{21.168}

or

u = 4.6 m/s

b) Now after the bounce, the ball moves with the same velocity

thus, v = v₂

thus,

final speed (v_f) = v = 4.6 m/s

Then conservation of energy says  

\frac{1}{2}mu_1^2+\frac{1}{2}Mu_2^2 = \frac{1}{2}mv_1^2+\frac{1}{2}Mv_2^2  

also

applying the concept of conservation of momentum

we have

mu₁ + Mu₂ = mv₁ + Mv₂

u₁ =velocity of the tennis ball before collision = -4.6 m/s  

u₂ = velocity of the basketball before collision= 4.6 m/s  

v₁ =  velocity of the tennis ball after collision  

v₂ = velocity of the basketball  after collision

substituting the values in the equation, we get

Now,

solving both the equations simultaneously we get

v = (\frac{2M}{m+M})u_1+(\frac{m-M}{m+M})u_2

substituting the values in the above equation we get

v = (\frac{2\times594}{44+594})(-4.6)+(\frac{44-594}{44+594})4.6

or

v = -8.565-3.965

or

v = -12.53m/s

here negative sign depicts the motion of the ball in the upward direction

now the kinetic energy of the tennis ball

K.E = \frac{1}{2}mv^2

or

K.E = \frac{1}{2}44\times 10^{-3}kg\times 12.53^2

or

K.E = 3.45 J

also at the height the K.E will be the potential energy of the tennis ball

thus,

3.45 J = mgh

or

3.45 = 44 × 10⁻³ × 9.8 × h

h = 8.01 m

5 0
3 years ago
How long does it took for 250-watt engine to do 2500 joules of work?
Llana [10]

Answer:

10 s

Explanation:

power = work / time so time would be time = work / power

6 0
3 years ago
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