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Murrr4er [49]
3 years ago
14

Which of the following choices is an accurate example of how the use of cultural tools is important in the development of one’s

cognitive developmental process?
A.
For the development of language skills, it is helpful to use symbolism in forming words to match mental pictures.
B.
Categorizing shades of blue from shades of purple helps one to make accurate concept formations.
C.
The use of an abacus to solve a mathematical equation is useful in helping the brain form a mental picture of the problem.
D.
Using cultural tools frequently causes connections in the brain’s nerve endings to strengthen.
Physics
2 answers:
kifflom [539]3 years ago
5 0

the correct answer is c according to ed genuity

mihalych1998 [28]3 years ago
5 0

Answer: Option (C) is the correct answer.

Explanation:

Cognitive development means mental development of a child or person. cognitive development helps in making or working of thought process like problem solving, decision making etc.

For example, when a child uses abacus to solve a mathematical problem then he his thinking mentally in order to frame a picture of the problem so that he can solve it.

Therefore, we can conclude that the use of an abacus to solve a mathematical equation is useful in helping the brain form a mental picture of the problem, is an accurate choice of the given problem.

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Explanation:

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A mass of 150 g stretches a spring 1.568 cm. If the mass is set in motion from its equilibrium position with a downward velocity
nadezda [96]

Answer:

u(t)=\frac{1}{5} sin\ (25t)

Explanation:

Given:

  • mass of the body stretching the spring, m=150\ g
  • extension in spring, \Delta x=1.568\ cm
  • velocity of oscillation, u'(0)=20\ cm.s^{-1}
  • initial displacement position of equilibrium, u(0)=0

<u>According to given:</u>

m.g=k.\Delta x

150\times 980=k\times 1.568

k=93750\ dyne.cm^{-1}

<u>we know frequency:</u>

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{93750}{150} }

\omega=25

Now, for position of mass in oscillation:

u= A.sin\ (\omega.t)+B.cos\ (\omega.t)

u= A.sin\ (25.t)+B.cos\ (25.t)

at t=0;\ u(0)=0\ \Rightarrow A=0

∴u(t)=B.sin\ (25.t)

∵ at t=0;\ u'(0)=20\ cm.s^{-1}\ \Rightarrow B=\frac{1}{5}

u(t)=\frac{1}{5} sin\ (25t)

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