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artcher [175]
3 years ago
15

If the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gr

avity at the surface would become
A) 1/2 of what it now is.
B) 2 times what it now is.
C) 1/4 of what it now is.
D) the same as it now is.
E) 4 times what it now is.
Physics
2 answers:
Len [333]3 years ago
5 0

its a i just have to type more but its a

Ray Of Light [21]3 years ago
4 0

The answer is B) 2 times what it is now.

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A blank reaction occurs when a substance, usually containing carbon, reacts with oxygen to produce energy in the form of heat an
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Combustion , I just got this on apex

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What is the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg
Marrrta [24]

Answer:

The acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

Explanation:

Given

  • Force F = 4000 N
  • Mass m = 1240 kg

To determine

Acceleration a = ?

Important Tip:

  • The acceleration of a boat can be found using the formula F = ma

Using the formula

F =  ma

where

  • F is the force (N)
  • m is the mass (kg)
  • a is the acceleration (m/s²)

now substituting F = 4000, m = 1240 in the formula

F =  ma

4000\:=\:1240\:\times a

Switch sides

1240a=4000

Divide both sides by 1240

\frac{1240a}{1240}=\frac{4000}{1240}

Simplify

a=\frac{100}{31}

a=3.2 m/s²

Therefore, the acceleration of a boat if the resultant force on it is 4000 N and its mass is 1240 kg is 3.2 m/s².

5 0
3 years ago
Question 4
maw [93]

Answer:

Plankton is the correct answer I think

6 0
3 years ago
Determine la inercia rotacional de una varilla de 4 m de largo y 2 Kg de mesa si su eje de rotación esta situado a la mitad de l
Maslowich

Answer:

   I = 2.667 kg m²

Explanation:

The moment of inertia of a body can be calculated by the expression

         I = ∫ L² dm

For high symmetry bodies the expressions of the moment of inertia are tabulated, for a rod with its axis of rotation at its midpoint it is

         I = \frac{1}{12} m L²

let's calculate

         I = \frac{1}{12}  2  4²

         I = 2.667 kg m²

8 0
3 years ago
A 60kg student is 5m from a 120kg door, how much gravitational forces act between the two?
slavikrds [6]

Gravitational force = G · m₁ · m₂ / r²

' G ' is the 'universal gravitational constant, 6.673 x 10⁻¹¹ m³/kg-s²

m₁ = 60 kg

m₂ = 120 kg

r = 5 m

F = (6.673 x 10⁻¹¹ m³/kg-sec²) · (60 kg) · (120 kg) / (5m)²

F = (6.673 x 10⁻¹¹ · 60 · 120 / 25) · (m³ · kg · kg / kg · s² · m²)

F = 1.922 x 10⁻⁸ (kg · m / s²)

<em>F = 1.922 x 10⁻⁸ Newton</em>  (about 0.0000000692 ounce of force)

7 0
3 years ago
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